2006 Exam 2

2006 Exam 2 - Chemistry 162 Exam II March 8, 2006 Student...

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Chemistry 162 Exam II March 8, 2006 Student Name (Print): ____TAVSS ________________ Recitation Section Number: t Recitation Instructor: ____TAVSS ______________ The exam booklet has 25 questions for credit and one additional question to check the color of your exam booklet. Please answer all 26 questions on the OpScan sheet. Use the best answer of the choices available. There is no penalty for guessing. At the end of the 80-minute exam period, please hand in only this top sheet and your OpScan form. If you finish early, please do not disturb your fellow students. A proctor will check your picture ID, OpScan form, signature and calculator during the exam. The use of calculators with permanent memories (graphing calculators), cell phones, pagers, PDAs or other electronic devices other than a basic scientific calculator is expressly forbidden. The last page of the booklet contains a periodic table along with other useful data. The use of any other notes or information on this test will be considered a violation of the Academic Honesty provisions of the student code. Exam scores will be posted as soon as possible. ON THE OpScan FORM (Use a #2 pencil or darker) Sec Per. Instr Sec Per. Instr 1. SIGN your name across the top of the form. 01 M3 RA 30 Th3 HS 2. Code the following information ( blacken circles) 03 M5 RA 31 Th3 ET Your Name (LAST NAME FIRST) 04 M5 LH 33 M6 RP Your SOCIAL SECURITY NUMBER 06 W3 LH 34 M6 RA [Start under Box A and continue to Box I ] 07 W3 HS 36 W6 NM Your RECITATION SECTION NUMBER in 08 W5 LH 37 M8 RP [Sections 01-08, code a 0 under box K ] 11 F3 NM 39 W8 NM Your EXAM FORM NUMBER under box P 17 M1 HS 19 M3 NM LH = L. Huebner, RP = R. Porcja, RA = R. Agarwal 20 M3 HS HS = H. Sangari, NM = N. Marky, ET = E. Tavss 23 W1 ET Periods: 1 = 9:30-10:25, 3 = 12:15-1:10 or 12:50-1:45 25 W3 ET 5 = 3:35-4:30, 6 = 5:15-6:10, 8 = 8:25p-9:20p 26 W3 NM Your EXAM FORM is C162s06e2v1 1
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1 Chem 162-2006 Exam II Acids and Bases - Chapter 14 Solutions of acids and bases, K a ,K b ,pH,pOH,% dissoc. ET: Molar % dissociation A 0.020 M acid HX is10.0% ionized. What is the K a for this acid? A. 1.8 x 10 -5 B . 2.2 x 10 -4 C. 3.6 x 10 -4 D. 7.2 x 10 -5 E. 4.0 x 10 -3 HX + H 2 O H 3 O + + X - 0.10 X 0.020 = 0.0020 HX + H 2 O H 3 O + + X - Initial 0.020 0 0 Change Equilibrium 0.002 0.002 HX + H 2 O H 3 O + + X - Initial 0.020 0 0 Change -X +X +X Equilibrium 0.020-X 0.002 0.002 HX + H 2 O H 3 O + + X - Initial 0.020 0 0 Change -0.002 +0.002 +0.002 Equilibrium 0.020-0.002 = 0.018 0.002 0.002 K a = ([H 3 O + ][X - ])/[HX] K a = ([0.002][0.002])/[0.018] K a = 2.22 x 10 -4 C162s06e2v1 2
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2 Chem 162-2006 Exam II Chemical Kinetics - Chapter 12 Reaction mechanisms ET: Molecularity Which one of the following is least likely to be a step in a reaction mechanism? A.
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This note was uploaded on 05/22/2008 for the course CHEM 162 taught by Professor Siegal during the Spring '08 term at Rutgers.

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2006 Exam 2 - Chemistry 162 Exam II March 8, 2006 Student...

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