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Unformatted text preview: where indifferent 4. p 1 (c) +(1-p 1 )(c) = p 1 (d) + (1 - p 1 )(a); p 1 = (c-a)/(d-a) 5.-2/-3 = 0.6667, numerical indifference point, P 1 = is when if p 1 is greater than 2/3, then game is probably more likely to be the scenario....
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- Spring '08