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METALS TUTORIAL 2.pdf - MS3013 Tutorials – Corrosion...

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MS3013 Tutorials – Corrosion FailureTutorial 2
2-1. A univalent metal, M, has ba= +0.2 V, bc= 0.2V, and io= 20 mA/m2.Calculate values for iaand icwhen the metal is anodically polarized to +0.20 V. Determine the experimentally measured net current density for thesame polarization.
2Figure 2-1 plot of the anodic and cathodic current densities for M.iaic
Method IIby calculation:Tafel equation is usedĪ· =±b logą µ?ą µ?ą µ?So,ą µ?±࠵?= logą µ?ą µ?ą µ?ą µ?ą µ?ą µ?=ą µ?ą µ?ą µ?±࠵?.ą µ?ą µ?ą µ?ą µ?ą µ?Ī· = E – Eo= 0.2 – 0 = 0.2 Via=ą µ?ą µ?ą µ?.ą µ?ā‹…io=ą µ?ą µ?ą µ?.ą µ?ą µ?.ą µ?ā‹…20 =10Ɨ20= 200 mA/m2ic=ą µ?ą µ?ą µ?1ą µ?ā‹…io=ą µ?ą µ?ą µ?.ą µ?1ą µ?.ą µ?ā‹…20 =10-1Ɨ20= 2 mA/m2inet=ic-ia= 2-200 = -198 mA/m2Note: Eois obtained by reading from the plot
2-2.

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Term
Winter
Professor
NoProfessor
Tags
Cathode, Anode, alkalinity

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