Unformatted text preview: work) (4 pts) Ne= 4NmNf/(Nm+Nf) Nm= 2 and Nf= 15 Ne= 4(2*15)/(2+15) Ne= 120/(17) Ne= 7.0588 Over five generations (two will be accepted also), use the harmonic mean 1/Ne=1/t Σ 1/Ni or 1/Ne=1/5(1/7.06 +1/30 +1/30+1/30+1/30) = 18.18 (2gen=11.49) Ht = Ho (1-[1/(2Ne)])t Ht = .5 (1-[1/(2*18.18)])5 Ht = 0.43 (2gen=0.46) 8c) Finally, you hope to counteract the loss of variation by establishing some gene flow between the two existing wombat colonies. You observed an Fst of 0.15 between the two existing colonists. How many migrants per generation are implied by this degree of differentiation? (Show all work) (4 pts) N e m =(1- .15)/4* (.15) N e m = 1.4167 or about 1.4 migrants per generation are needed to restore gene flow. Some useful equations: Fst= (Ht-Hs)/Ht D12= Ht - Hs Fst =1/(4Nem + 1) N e m =(1- F st )/4F st Ht/Ho= (1-[1/(2Ne)])t F = (2pq-Ho)/2pq E(n)= m-Σ (1-p)2Ne Ne= 4NmNf/(Nm+Nf) 1/Ne=1/tÂ1/Ni...
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- Winter '08
- Population Genetics, New South Wales, effective population size, NEm, /Ht D12= Ht