tut1_sol

tut1_sol - 1 Sol Tut #1 SEE 1003 2004/2005–I Chapter 1,...

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Unformatted text preview: 1 Sol Tut #1 SEE 1003 2004/2005–I Chapter 1, Solution 2 i = dq/dt = 3 mA i = dq/dt = (16t + 4) A i = dq/dt = (-3e-t + 10e-2t ) nA i=dq/dt = 1200120 π π cos t pA i =dq/dt = -+- ett t4 8050100050 (cossin) A μ Chapter 1, Solution 3 C 1) (3t + = + = & q(0) i(t)dt q(t) mC 5t) (t 2 + = + + = & q(v) dt s) (2t q(t) (t)20 cos 10t/6q(0)(2sin(10/6)1)C t π π μ =++=++ C 40t) sin 0.12 t (0.16cos40 e 30t- +-=- + = + = & t) cos 40-t40 sin 30( 1600 900 e10 q(0) t40 sin 10e q(t)-30t 30t- Chapter 1, Solution 4 () mC 4.698 =- =- = = = && π π π 06.0 cos 1 6 5 t & 6 cos 6 5 dt t & 6 5sin idt q 10 Chapter 1, Solution 6 (a) At t = 1ms, mA 40 = = = 80 i t dq (b) At t = 6ms, mA 0 = = t dq i (c) At t = 10ms, mA 20- = = = 80 i t dq 2 Chapter 1, Solution 9 (a) C 10 = = = & & 1 dt 10 idt q (b) C 22.5 =- + = ×+ ¡ ¢ £ ¤ ¥ ¦ ×- +× = = & 25 10 15 15 2 15 10 1 10 idt q 3 (c) C 30 = + + = = & 10 10 10 idt q 5 Chapter 1, Solution 14 (a) () C 2.131 =- + = + = = = && 2 e2110 2e t10 dt e-110 idt q 0.5-0....
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This note was uploaded on 04/06/2008 for the course EE 112 taught by Professor All during the Fall '08 term at Cal Poly.

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tut1_sol - 1 Sol Tut #1 SEE 1003 2004/2005–I Chapter 1,...

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