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# 9c - I—I'f Dinah Lin PMﬁ-dd VR In Assume “Wt Dru—Du...

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Unformatted text preview: I—I'f ' Dinah; Lin PMﬁ-dd +VR- In Assume. “Wt Dru—Du ME. Same, W K f E = VR + VFQ 1 1:91:11). +Ip: '1‘ --- + In" :J’LI‘D 'I'u.—-— IR = 1m .1..-" +IF n :0 am: Assume. E=IOVJ R=\$WJ1J h=2lqu I)! am! D; m shinny: «Kain havﬁﬂj Sm"; ﬁled/r1}. PMmei'Lrs- 17eme In. M5! 1131. goMbh : Inf: ID]. and VFE=D.7V_ Example 2 " For the circuit shown below determine the circuit current and the voltages across the resistors R1 and R2. The diode in the circuit is silicon. Solution: Replacing the diode by its simpliﬁed model we have the equivalent circuit shown. Using Kirchhoffs voltage law around the loop, we have: 1(R1+R2)=10V40.7V+5V=14.3V. (0v: Vn'+o.7v+vm_sv Hence ‘ \ Vb 14.3v '=" VRI+VI22= )0V-0.7V+5V I= =2.07mA. 5.9m The voltages across the resistors are: VRI = I R, = 2.07 mA x 4.7 k!) i 9.73 V. VR2 = I R2 = 2.07 mA x 2.2 kw = 4.55 V. The method we have used to analyse circuits with diodes connected in series, can be applied to diodes that are connected in parallel in a circuit. Example ; Find the total circuit current and the current through each of the diodes in the given circuit. 3309 1 3300 I 10 V Si diodes Solution: Using the simpliﬁed diode model, we replace the diodes with two 0.7 V batteries. - The voltage'across the resistor is VR = 10 V — 0.7 V = 9.3 V. The total circuit current is I = current through R = = 28.18 mA. 330 Q ME Sham and, R=IRJ1.J A B c D DI R D1 1 V51 + .1. 13¢ -:_. ___U'51 ' - 8v 5 ‘ ~ ‘ DMIW' V5, :: V9, + IR ‘1‘ V9; 1' V52 I = Vs: - VI?! “in: - V51 R F ZSV-D.7v—p.'fu.—8v "Em—H— {wan = JEbmA 1412142 :(:§.6MA)(IRJ1): my! HE-hﬂ‘. VA :V5l= 13v Va:v5.—vp.=2sV—~u.1v=2q.3v I+Jﬂ dugam\§ 3.8.50 £583 team 2: was o H M E m; 0mg?» #386 some 05 .3 K on i ....... -- 3E3 23 @3858 NE maﬁw REES 3 :8 as: 32 BEL . as 23 o.“ . .3 2:. mm among uumﬁﬁsﬁ m 0% .3 oﬁmtﬂoﬁﬁo NE 2% an Egg ﬂ on: 32 2: go 2038385 2; . \$333 m 33 “gum: oﬁ u . 3:8 2:033 m "5 Egg r. + b 513... . :1. 3:30 mien—o oomﬁmmmou .325 BE . 25% m SE “Soho mﬁ 52300 . mwmﬁwqw on: 30A Me: For the circuit of ﬁgure C‘ia. the battery 1tic-Itage is 2 watts. and the resistcr is acne. a} Sketch berth the lead line and the diode characteristic. The characteristic curve is given to yeti in figure cm. b} Show on the iced line the lccaticn cf the Guccth and from your sketch ﬁ resistor Ft. nct the current through the ID . . . . . . . . . . . .h i ___:_+ VD [10 0.7 W Figure 01a Figure 01!: 2-25 whim ...wﬂmadm miguwgm; .conmumzcuE EEEhﬂ £3; “www.4qu v.35 .35.? h ml— MH— :U I ...
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