exam2a - Chemistry,r 1302-02, 03 Spring Exam 2 March 9,...

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Unformatted text preview: Chemistry,r 1302-02, 03 Spring Exam 2 March 9, 2006 Name Kill-HE {T'fllitii 5;" I1. I'- Section 9:00 11:00 / Multiple choice {ipgints each 1. Mark your answer on the scantron. Be careful to erase completely ifyou change an answer. Curly the semitron will be graded. Check your wagers: gun': he careless] Show you: won: on flu: exam booklet. 1. To prepare a buffer with a pH of approximately 1115‘ 11.0, the best choice of a weak base and its conjugate acid in eguin‘lolar amounts would be )6) (CaHshN Kb=5.2xl[}'4 Kflflflwg'” Pfiaepfi: [Oil B. OBr‘ Kt. =4.{}:-t [0'5 Kg: 25X mun FKH‘PFV 3o C. CN' Kb = 1.6 x 10—5 Kg: tpglr-sxm-w P112112 D. N0; Kb: 1.4x 10-11m— 1. I4ym“= g2: maps E. Kb = X 10—5 KG."- I',i.px10"m II'JI'1 ' 51.3 2. What is the pH of a 500 ml. aqueous solution containing 2.70] g of methylarnine 1 Jfllqp h)“.dmi:}.llfll.i‘:l,A-fi1 CHENHJCI‘ (fw = 67.52)? K], for mefliylaniine = 4.4 x 104 11.8 ensue; c." + Hole-e tau-«Jag all + it'e‘ Kati-45‘ 1V4 {Tin B. Half" 14}: PI"?- ii‘; iii-3411 D' 2‘2 ‘--‘”W*=EUH‘]* [Guiltifiimu'g . ' E‘ 5‘8 0-09] f.-3H1-a.-':-:u-=: pUH‘-'E.’i~'-PH-=H.‘o 3. A solution is saturated with AngOi. Calculate [Ag‘] in the saturated solution. For Ag2804.1<3p = 1.4 x 10'5 at 25°C. A 33 x 10-3 M53504”)? 2525+ + Ks? : 1- is it)”; a. 1.4 x 10: Kg? __ Mai-l [68%-] C. 1.5 x10 " :(Zaytfl T 4 '3’; fl auxin-1 our? _ q * E. none of the above flim— t 3 = [503‘] “ J 3 [3.01513 3‘1: Cl. TEE”?- JV 3.0}{10 4. What is [ZnEJ’I in a solution that is 0.25 M in [.7_’.n{1'*~1H3J4|1+ and has [NH3'I equal to 1.5 M? [if for [Zn(NHJ}4]1+ = 4.1 x 103 A. 0.050 NH sue. :[Zn twang“ as - 4.: x. lo? a. 4.1 x 10-” a». .ggzy. .; engage-1 C. 4.1 x 113'8 H312??— fi L2 x mm 4 ts. i135: iii-s35}. E. none of the above I F f I; ‘ 5 )fi- A In the titration of 100.00 mL of 0. [000 M HCl with 0.2000 M NaOI-I. after 50.00 mL of the NaOl-l has been added, the pH is A. B. 2%? E. 0‘3 i “H'Hfl I..i.|.\_i'j'.\.'l E... I H: 3,5 Elfin? i,_._ a a l ' 4- 5-9 1‘5}- -‘-‘ + Hire -. a: 1.3.59.3 9—[1 ' " Zszgt'lEDF-rDI—r tic-— rang—l“ toms-oi tfirnmul [I‘D AIL] Lamb— 4 __ {Hfiflvflfltfl 34331 . MEMO"? PH-tii 11-14 6. Titrate 40.00 mL of 0.2000 M ammonia (NH?) with 0.5000 M hydrochloric acid (HCI). What is the volume of titrant required to reach the hypothetical equivalence point? A. 2? D. E. K}, for NH3=l.8x10'5 40 em Union as; 40mm. 13 m 9-29“ “H lg0030mLL fiqmmlm“ Pom“ Mimi Willa-maul H'Cl . m 9.00 ml. ffiflmfli-fliflrvfl - Highs-ram) none of the above v2 : H0.li.ilth;__ T. Titrate 40.00 mi. of 0.2000 M ammonia (NH?) with 0.5000 M hydrochloric acid (HCI). What is the pH of the resulting solution after the addition of 5.00 mL of the acid"!I A. B. D. E. Km. for NH3 = 1.8 x 10'5 43.0 we CL loM MHz} ' :- 7 44 5.0+”; fllfifflfi.‘ Hapl UH . 83 NH?" H304”: NHg‘rHlfl Kai‘SJavIQ‘ic‘ Gil rflwl 9-6 ingot-M} il‘. .‘meaf' 5.1 . none of the above Kn —. [a as] ems-:“v’s—QLaou ..+. will. _..{L_I)_ [ll—3.025% P 8. Titratc 40.00 mL of 0.2000 M ammonia {EH3} with 0.5000 M hydrochloric acid III-ICE). What is the pH of the resulting solution after the addition of 20.00 mL oflhe acid? A. B. C. 2? Iti’.|]i'orl"'~llljh=1.81:10'5 40.0:HL. {0.10M NH}; PH: 7 5.0 “3,9.0iht. doom He! r'l'JllLl-v. '5 Has)? :5"- " l‘llkj Kr.) : it It. "it: Emmi le. d 1'5 '- l.i 1mm .-. .jlll'll'r'ml none of the above 1 d '. )] .‘Fjlij, .I .'_; - .J ._ __. ' ’.: " . 1 EdifiL—r it”. r A. The solubility of cerium (iii) iodate. Ce{i03)3. at 25°C is 8.49 x {04 moliL. Whatis K51} for I 3.: . _ A. 5.2 x 10'I3 QEUOJE‘HE: Cf; * 3g?" —H ‘5 1.4 it 10 3 .1. ._ '3'!“ ' -.. C. 1.0 x1046 Kit“ [‘1‘ HIDE] 2 D. 3.3 X. 1043 HEP: :1“; (gaqflgvfljfii = Lil-pt 10-” E. none of the above ' It]. Calculate the pH of a saturated solution of SrtOH); in water. KSP (5mm, = 3.2 x [0‘4 2g 12.9 5HOHiflsifi svlw ma- scu- nevi" s. 12.6 '3 C. 1.1 aivltlrfrs L’DrHHOHflil D. 1.4 = fire-3 E. none of the above a ‘- O . 0%?) i [0H3 '- 15 " CI. O‘Sial pOHs i. 0L9 PH: ilfi 11. For AgZCrOJ. K513. : 1.1 x 10": at 25°C. What is the concentration of Ag” in molfL at . . . ? Huh r I I_ i - egullrbnurn. Aqlcroq(6}\_ intact (Id: réFMHG “L A. 3.1x10‘5 .25 5 3. 2.8x10‘5 _.1 ‘- _,)© 1.3x 10-4 K6? ‘mflfl foes] D. 6.5x10‘5 Mufti-.4533 '3' —. .I 5: _ _— E. none of the above "5 4 ~ J i '1- t‘sg*1=tsr 175:: I0"‘" 12. What is the equilibrium constant for the reaction AECNtsi + CN'taq) [AE{CN}2J"{aai if Kf for AglfiCNb‘taq) = 2.0 I": 1033 and K5? for AgCNts) : 1.2 K 10'”? N 14;;[033 RGJCNi‘uiF—a W+W‘ K39: L'Zsioqm s. 6.0 x 10-55 ,. fawn/*4. gm " v": [asters 31‘ K; = :1 .o x to 54 " ____. --_.fl__,. ____‘_ ii. t a we) + cs ~ ..-.~..—~= t attest] Kc, (mm) B. 2.9s105 = 2_ “rm” A. Consider the foliowing reactions: .Ag’téqi + 2 Mateo AglNH3}2+{a-:|} sf: 1.7x 107 Agile} fixgfiaq} + l'iaq] Kgp = 3.5 X 10'” What is the molar solubility of Aglis) in a solution in which the equilibrium [NH3I ‘5 2'00 M? e133: -+ 2 NH3;:-':= ring-is H .1}; + 1 ‘ 1/; H4611 iii"? A. 3.3 )1 10'5 M 13. 1133 M K; 3 [9.33% LY] _,;© 7.6 x10"5 M " o. 9.5 x 10—5 M _ __ E. none of the above ' I ' I“ _ L .. ..._ 14. What is molar solubility».r of 111(OH)3 in a solution buffered at pH = 5.0;“- if]: ,I 113—1 KSP for indium {III} hydroxide (In(DI—l)3[s)) = 1.3 x 10'“. L flint-11:3: 11-1“ A. 1.3 x EO'flM mom. 15):: is“ .1. my gr testo'fl e. 5.? 1-: 10-12114 ‘3 C. 1.9 )1 10-9111 K5P1E1Hzi-1E0H-13‘ D. 8.? x 10"9 M $3 1.3 :1 “Twin ._ . - I It» a }.ax1113‘1t;in?*i{1.ss1o 1) .. H _ rum llfial] “ il'flidlwai‘ l-‘b “Kl-1.} 15. Calculate Kt of [CdlfCNh] 2', if it is found that in a solution that is 0.0500 M in [ti‘.1:l(Cl\l}.1}'2 and 0.80 M in free CN". the eoneentratieaof (312]+2 is 9.4 it 10‘” M. I 0:1+1 {3‘31} + 4CN*taq} a—W £Cd(CN}4'i'31aq} A. 2.0 11 103i] .. __ 1 B. 3.0x 11:11ii Ks - lEEdLENisi l w 1.3 .1110” {Eda-“j mus- D. 1.3 K 10‘3'Ijl E. none of the above "a 0-3530 0 iq.‘fi-sl."”)(0.id)+ *— 1.?) x it)” /:i. What is Kc for the following equation? AgClts) + Fine) 1....— Aglis) + Cl'iaq} KS], for AgCl = 1.8 I: 10"“ and Kai, for Ag] = 8.5 x 10'” Q llxmfi fifigifiyr“: 0:55”? 1- Eli" K510i IKE-{WAG 3- 4-“10'? I r. v .: a 10.) k’ —-‘i 5* 1WD” C. 1.51:10’35 t C 55‘“ _ a. W. D. 360 fifllvitri"? salon or Kai-iii“ Wm J E. none of the above ‘- 13. ,i1 x10” 17. Which of the following will not act as a buffer when mixed together to form a solution? A. 50.0 mL of 0.250 in no] and 50.0 ml. of 0.500 M PO4‘3 ninfisnb‘t' 50.0 mL of 0.500 M NH3 and 25.0 mL of 0.500 M NH.CI Z© 50.0 mL of 0.500 M 0013 and 50.0 mL of 0.500 M ac: m 50.0 mL of 0.500 M NH:. and 50.0 mL of 0.250 M HCl outfit _ 50.0 mL of 0.500 M HPOJ2 and 50.0 mL of 0.500 M FUJI3 18. The pH of human blood is controlled by several buffer systems including the II I HgCng HCO3' system. If the [HCOg']f[H2C03] ratio is 11.0 in an aqueous solution, what is the pH of the solution?I For H2C03. K3 : 4.4 x 10'? A. 3.? Hlflflatlilofi HUD}- + Hat)? B. 5-3 _ I. — l- 79 0.4 ‘l‘flloq '- .i..l‘-‘£Ei_._l.ill_3l3:] D' 13 LHILDfi E. none of the above .._ .ji‘fiirififl _ ' 'TJ 4.055110" ‘” L 3b PH: :4— 19. The pH of human blood is controlled by several buffer systems including the HEPOJHPOE' system. Calculate the [H3P04"]I[HPO43'_] ratio in an aqueous solution having a pH of 736‘? For HgPD4', Ka = 6.2 x 10'3 aflfiw P 6) 0.403 may]: 3 H1 'l' H10 :2 H POE; "’r HEOJF lW-lffisfélj B. 2.48 1.00:0“ I I t I“ W 0470ing . C, {1510 L0. .5: ML; .~. LH {infra 753;. 1%. o. 1.90 initials—1 all an??? £10 F. none of the above 4; ~ . i 2--’ __ i i... :2 :10 - - .3 iv.- _2 s .. to‘l‘ Ll’lll "Uzi, . Hit» O 405 I‘ll. KW. [111' PivHr 1m 7 41} \ Ill—5. h-‘lix HM} ml. Hl' [LURE] M F’bIINU-Jfimp n ith 5U ml. 01' HEN?) M “Brand 'I."' "3'" . _ I.-_I _ JI . . FL {‘35P 3‘ Fix-p.11. pruuipilnlc I'nrmh'. II II a .. I _. . I I. I. [II-{Tl B. USP '3.» K51]. nu prucipilellc I'UE'HH. ' [35p c: Kala. nn precipitate forms. _ '. i ' -. . .3 11 Qfip : Kw. [he rsyh‘tcm ii; at mtuilihrium. I in ' 2‘11"“??? .7: “'1' EL} u: K45}. :1 prvcipimtc forms. _ .1 .I .._- .' K31 2|. A mlulion M1405 M IICUi'H-l {Fnrmic acid} and 0.336! M in m: snll 'Hrimwu {sodium formnic}. What ii; the [H or I.th huf‘ftr Holutitm‘.’ K... for “HUGH : LS x H14 259 1'55 a"? I ' i.‘ -' ' ' kit-i! B. [H.373 _ [13'- 3-34 \' " —. - I}. “IN:- _:‘-._ - |.-.= E. 3.7—1: . _ . _ . 23. A mlutimn i‘i H.405} M HETHJH [11mm]: acid. Ha Fur HILIHUH = 1.8 1: H14} and [3.331 M in the Hit“ I-ICII'JIUNH [audiltrn E‘nrrrmlu]. H3; uddng 5”.“ mL 01' Elli—H1} M HILII m iHEI mi, of [he mlulinn. 1hr pH chalflgcd in ' I ' |/.._~.'-| 15. r“ | II: Pt. H1251 H'. .131 DE'. - '1'); '—' “.11 L: -- .‘ ' 1! I .r'n 'E i {:1 Iii—H - FT. .133 z; “I j. I I 23. Wt hum: L1 Hchlulion UH '-.1-‘ and? ’11“ u hurt-s. hmlt mm an: {H} | H M. We mid NHIHUI final} to pi'L“Ci}‘siTfliC um: bul nut 1hr minor inn. What is the rrmlur cmwnit'alimn ni' iI-m Hm 1011 Ehnl panpipllulcx whcr} lhu mun: .mhlhlc “CH”. lmgim‘ In [:IrL‘L'ipitémi'? K5], Fur {Tufirh = 9.! x 10".): Kg]; l'nr i'hSIh = 1.5 1 HI": .-\. Isa .~. 1n '-* i :: .-.-..i ' '_. .- .. ., .' - k; 'i'n"? -. " I _... _— . -_. :/-' "'I ! :-' -. -'--'_ -.' .- I - x.._ '. '___ _'_. _?'-.' 1:3. Lam-4" _ _. _, __ _ I I). Iflxifl" . -. ' ms." I _ 5-. I: I. . IL .I_ -! .-.___-I )Q LEM EU" -- _ _ .- --— [4. Choose an indicator which will change at a pH of about 4.7, assuming that the color change is “half way" between the two colors, and egual amounts of acid and conjugate base are present. PH: PK“ A. bromophenol blue Ka : 1,4 x [0‘4 F. H. 73331-5 fl bromoercsol green Ka : 2.1 at 10'5 p H 1 “his? C. brontothymol blue Ka = 7.9 x 10'5 PH«- "l . to D. chlonopltenol red K3 : 1.0 x 10'“5 P H - La E. thymolphthaleitt [(3 = 1.0 x 10””) P H--— t t} 25. Most fish species will die if their habitat becomes more than about 300 times more acid than pure water. For these conditions, the pH would be approximately a. 2.5 \ Hfll B. 3.5 P (“’- .- I a“ /l . "Ea—l 7g 4.5 [1190*] ‘-'~..l .0! l {1 1) ’15 " 3’ x m. _.-i D_ 55 — taste... J‘slb 31's.? E. :0 "i 26. What is the molar concentration of Sc3+ abot'c solid Sc(OH}3 in a buffer solution made from 250 mL of 0.20 M NH; and 500 ml. of 0.10 M NH4C1? K, for NH3 = 1.8 I III”5 K5p for SeniOH}; = 8.0 x 10'31 _ l’fiflmL CI. ' - 3' a. 5.1 x to I“ 50.3% 0.33;; 3.3.3;m‘ysffiffiilfitldz ! a. 2.5x10'“' [5413+] :|,4le-I C. 4.4 x 10-26 stamina: or? + soa- tag- so». to“ o 4 3 x 10-3 1"”? " ham”? 73 14x19” who H10: Nah oH‘ K.'-f-tt‘-U'g fitjtlhul alias-cl 1‘ Ill-RTE 27'. Hotsr man); mmol of HCl must be added to 100 mL of a 0.100 M solution of ethylamine (Kb : 5.6 1t 10“) to give a buffer having a pH of 11.0'? stunt-r! tit-F“ H111}. l _3 ‘35 iii it-” tsHt=ttlfl ‘- P 1- ‘- z ‘1- c. 10.0 Eb + H110 fiEmHtO Kaf- 1.8mm “ o. 3.5 limf“ if"; g, L. E. [.9 1'. 3): HF” =yi_1.]LZHa,O*]_ _LE.1 _ Er__n " “Emilia W300: "‘01 0 pH li‘s‘l‘l as = HECIFlL'I EH Elf-JUNE . IMPD FITANT mm scantronmrmq mm TEST RECORD FORM ND. BEE—E SCANTRUN 'I'I'J USE SUBJECTI'U'E SCORE FEATURE: - um io'lal Imagine aumtm palms vflnly one mark par Ern- on let!- - 163 points muirnum umi'fin. z'll'imtnlfnmrr | I I _ -: __ 141% a, C'rfiihfiai - MAKE DARK MARKS EXAMPLE OF TOCHANGE -ERASE COMPLETELY nMu an”. Inn “mu H L nm... In: nflu "mu u u mu. nun. 1a.. .IUJ .Imu .Ifiu m.” 5 nun nflu HUu .Imu rd... m nwu nflu “flu “flu “in. E... m 1.”... Han. .IUJ .ImJ 1.1:. ma. M nun nflu Hun. “mu “in. g m nmu nflu nUu “flu “in. mg... m nun “flu HUu “mu “flu NE. m In a EUSTGMER SEW-WEE 1MH2 63W “Nu * FUI. Emu. Fin, fl nun. “Du ll 1m." in... h.- nMu n u nUu * nd.” m DWI. ran. hm”. n1” m nwu .i nUu nflu n1”. .? H I * HUI. 1mm win .5 “Wu “Du nUu nmu i. N. “mu “flu nUu nflu i _. I|||||ll||||||||l||Illll||||||||||||||||l||||l||||I 4‘— FEED THIS ERECTION —: ALL HfiI-Ilfi ill-'EEF'LIEL‘IIIZ 5 “Ar NL'I Tflffififl F1- EFANTFUZIN I'EI'BRFIIFATIL‘IN1WEI >420 mm... mflkuzflhmg. wmoum MPEUm—wmzm ...
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exam2a - Chemistry,r 1302-02, 03 Spring Exam 2 March 9,...

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