Homework 2 solution
1.15.
(a) Superheated table, U(kJ/kg) = 2515.5, H(KJ/Kg) = 2687.5
(b) Single interpolation, U(kJ/kg) = 3175.2 + 0.25(3167.93175.2) = 3173.4
,
H(kJ/kg) = 3541.3 + 0.25(3531.63541.3) = 3538.9
(c) Double interpolation, interpolate pressure first for higher accuracy
T(
o
C)\P(MPa)
7
7.5
8
450
U=2979.0
H=3288.3
2973.4
3280.8
2967.8
3273.3
475
U=3021.7kJ/kg
H=3343.2kJ/kg
500
U=3074.3
H=3411.4
3069.9
3405.5
3065.4
3399.5
(d) Double interpolation, interpolate between saturation table and superheated
table
T(
o
C)\P(MPa)
0.6
0.7
0.8
164.95(from steam
table)
U=2571.81kJ/kg
H=2762.75kJ/kg
180
U=2599.0kJ/kg
H=2798.1kJ/kg
200(from
superheated table)
U=2639.3
H=2850.6
2635.15
2845.15
2631.0
2839.7
1.17
(a) superheated q=1, T=400+(30002966)/(3047.52966.0)*50=421
o
C
V=1.0315+21/50*(1.10921.01315)=1.064 m
3
/kg
(b) superheated q=1
T(
o
C)
U kJ/kg
350
2865.1 by single interpolation
T=370.7
by interpolation between 350 and 400
o
C
2900
400
2949.5 by single interpolation
V=0.1646 at 350
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 Spring '08
 Gallivan
 OC, 1 bar, single interpolation, 1.45 kg

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