equation08-2

# equation08-2 - CEM 152 Spring 2008 Exam 2 M = mega = 106 k...

This preview shows page 1. Sign up to view the full content.

CEM 152 - Spring 2008 – Exam 2 M = mega = 10 6 k = kilo = 10 3 m = milli = 10 -3 μ = micro = 10 -6 n = nano = 10 -9 p = pico = 10 -12 1Å = 10 -8 cm π = 3.1415926 1 amu = 1.660 x 10 -27 kg N A = 6.022 x 10 23 g = 9.8 m/s 2 R = 8.314 m 3 Pa/molK R = 8.314 J/molK R = 0.08206 Latm/molK slope = Δ y/ Δ x K = o C + 273.15 o C = (5/9)( o F – 32) o F = (9/5)( o C) + 32 1 Pa = 1 kg/ms 2 = 1 Nm -2 1 atm = 1.01325 x 10 5 Pa 1 atm = 760 torr = 760 mm Hg 1 bar = 10 3 mbar = 10 5 Pa P = F/A P = h ρ g P = n R T/V d = M/V d=PM/RT P 1 = (n 1 /n T )P T = X 1 P T average K.E. = 1/2 m μ 2 M T 3 R = μ
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern