Unformatted text preview: β x Β· 2 + β x 2 + β x = x (4x ) Β· (2 + β x ) 2 2( β x ) 2 = x (4x ) Β· (2 + β x ) 4x = x ( 2 + β x )β 4 Β± 2 + β 4 Β² = 16 as x β 4 Ex (2) : lim x β sin 2 x 5 x = lim x β sin 2 x 2 x Β· 2 5 = lim x β sin 2 x 2 x Β· lim x β 2 5 = 1 Β· 2 5 = 2 5 1...
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 Spring '08
 Julies
 Limits, lim, lim Solution, t1 t2

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