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Unformatted text preview: π 3= π 3 8. 3 = e ln 3 3 x = e (ln 3) x Z 3 x dx = Z e (ln 3) x dx Substitute u = (ln 3) x . Then du = (ln 3) dx and we get Z e u ± 1 ln 3 ² du = e u ln 3 + C = e (ln 3) x ln 3 + C = 3 x ln 3 + C 9. F ( x ) = ex 2...
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 Spring '08
 Mooney

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