Chem_208_13_07_web

Chem_208_13_07_web - 1 Today Ch 16.1-16.5(Acid/Base Thurs...

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Unformatted text preview: 1 Today: Ch. 16.1-16.5 (Acid/Base) Thurs: Ch 17.2 (Buffer Solutions) PS5 due Fri. March 9 Prelim 1 : Mean = 63.9/90 = 71% St. Dev. = 14.8 2 A couple of examples ….. Consider the reaction 2H 2 S(g) ⇔ 2H 2 (g)+S 2 (g), for which K c = 1.67 x 10-7 at 800 o C. If you initially place 0.0125 moles of H 2 S in a 0.500L container, what are the equilibrium concentrations of all species? Here, you need to assume 2x << 0.0250. This assumption is valid, i.e., 2x is 2.37% of 0.0250. [H 2 ] = 5.94 x 10-4 M; [S 2 ] = 2.97 x 10-4 M; [H 2 S] = 0.0244 M 3 2SO 2 (g) + O 2 (g) ⇔ 2SO 3 (g) K P = 0.25 at 1100 o C. If equal volumes of SO 2 and O 2 are put into a ontainer at a total pressure of 1.00 atm, what re the equilibrium concentrations of all pecies? Here, you obtain a cubic equation. You cannot assume that x << 0.5, instead, you can solve this problem by “successive approximations”, to obtain x = 0.062....
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This note was uploaded on 05/18/2008 for the course CHEM 2080 taught by Professor Davis,f during the Spring '07 term at Cornell.

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Chem_208_13_07_web - 1 Today Ch 16.1-16.5(Acid/Base Thurs...

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