lecture10_041507

# lecture10_041507 - b ∆ S° =-137 J/mol·K c ∆ S° = 25...

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Entropy Predict the effect on entropy for each of the following: a) evaporation of a liquid entropy increases b) 2SO 2(g) + O 2(g) 2SO 3(g) entropy decreases c) Freezing of a liquid entropy decreases d) 2NH 4 NO 3(s) 2N 2(g) + 2H 2 O (g) + O 2(g) entropy increases

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Determining entropy of a reaction In the metallurgy of antimony, the pure metal can be recovered by reducing the ore with another metal according to the following reaction: Sb 2 Fe 3(s) + 3Fe (s) 2Sb (s) + 3FeS (s) H = -125kJ Calculate S for the reaction at 25°C and 1 atm. Is the reaction spontaneous? S = -125 kJ/298K = 0.419 kJ/K = 419 J/K
Entropy of reactions Calculate S° for each of the following reactions: a) H 2(g) + ½O 2(g) H 2 O (g) b) 3O 2(g) 2O 3(g) c) N 2(g) + O 2(g) 2NO (g) J/K·mol H 2 131 O 2 205 O 3 239 N 2 192 NO 211 H 2 O 189 a) S° = -44.5 J/mol·K

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Unformatted text preview: b) ∆ S° = -137 J/mol·K c) ∆ S° = 25 J/mol·K Spontaneity At what temperatures in the following process spontaneous at 1 atm? Br 2(l) → Br 2(g) ∆ H° = 31 kJ/mol and ∆ S° = 93.0 J/mol·K Spontaneous at T > 333K Free Energy Consider the reaction 2SO 2(g) + O 2(g) → 2SO 3(g) at 25°C and 1atm. Calculate ∆ H°, ∆ S°, ∆ G° using the following data: Substance ∆ H f ° (kJ/mol) ∆ S° (J/mol·K) SO 2(g)-297 248 SO 3(g)-396 257 O 2(g) 205 ∆ H° = -198 kJ/mol ∆ S° = -187 J/mol·K ∆ G° = -142 kJ/mol Free Energy and Temperature The following graph of the change in free energy versus temperature (T) corresponds to which of the following situations?...
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lecture10_041507 - b ∆ S° =-137 J/mol·K c ∆ S° = 25...

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