Answer_Key_for_PS5 - Chem 208‘ Spring 2007 Problem Set 5 Due Fri Mar 9 at 2:00PM Name Lab TA Name Lab Day Suggested Additional Problems Chapter

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Unformatted text preview: Chem 208‘ Spring 2007 Problem Set 5 Due Fri. Mar. 9 at 2:00PM Name: Lab TA Name: Lab Day: Suggested Additional Problems: Chapter 15: 7, ll, 13, IS, 17, 29, 31, 33, 37, 39, 51 1. Al 35"c, Kc = 1.6 x 10'5 for the reaction 2NOCl(g) «:2 2N0(g) + (3mg). Calculate the concentrations of all species at equilibrium for each ofthe following initial mixtures: in) 2.0 mol pure NOCl(g) in a 2.0 L flask. 2 Mac/(7) $5“ ZN0(9;1 C1919) 1M [r11 1 0 0 0.5 —2.x 2):“ x E5255 1-2.5 E; x x t W; 5 ODISQM Checkzwhwoqa = 3.2% on [nod] = 0.97” b) 1.0 mol NOCl(g) and LO mo! NO(g) in a 1.0 L flask. ZMOU a? Zno+ Clz. \nQ-iYMJ Lo I o "1* +1“ " ,._ Eg‘m [.0—221 ¢ AO—Zx K [Mom]: [,0 M K»;- (1'0 a“ ‘3: Mom's [no] = I'D-M A [2:719911' [mp]: 1,4,;«10'51‘1 1x 'a ' $5M _(/.0)“(2<\ -.-_ mum’s /' Clack xfiizliO'S-z) HOW. ‘33.“0‘323 30K. c) 1.0 mol NO(g) in a 1.0 L flask. Hm, Swskm Canna’l’ mac-l, 3:) fun]:— LCM [Mocn=005’l 2. Place a check mark in the spaces below to indicate which of the following will be affected by the addition ofa cataiyst. a) The value ot‘the equilibrium constant. b) The value of lo; the forward rate constant. v/ c) The value of k, the reverse rate constant. Ll) The value of the forward rate. 12/ e) The value of the reverse rate. f) The value ol‘the ratio kp’kr. g) The time required to reach equilibrium. / h) The value ol‘AH" for the reaction. 3. At 2200“C. K. = 0.050 for the reaction N:ng + 02G!) <3 ZNOCQ) What is KI, for this reaction? What is the partial pressure of NO in equilibrium with N3 and 03 that were placed in a flask at initial pressures of 0.80 and 0.20 atm, respectively? Hm] gnwao KP: Kc: 0.030 “Zea + oz“) :9 2M0 (an lmi» 0.80 0:7—0 0 ma: +1 3! _.~...__..an..,........ .. _..y.._.....—.._...—.-w-.~w.‘. Eém 0.80% 020-): Z» 4X2”: 0.050 (O. lé —O,?f:‘0k 43.2.01 +4!) 4/,7— :. 0,050 oJL-x +K > Z. -2. 1 0: /é-x+x I ‘79} +X~0Jb=0 = " Jim ,, t ’53 Kr - _ 3’ 134$ 2(74 — of Hg I53 fall: 0-72” EU°3W°73M —« (author ’ Mm”- ):oaa one M mar“? At 298K, unequal amounts of BC 13(3) and BF3(g) were mixed in a container. The gases reacted to form BFClfig) and BCIF2(g). When equilibrium was finally reached, the four games were present in the following relative amounts: BCl3 (90), BF; (470), BCng (200), BFC12(45). :1) Determine the equilibrium constants for the following two reactions: 21303th + BF3ig) <2 3BFCE2(g) KP = ? 1303(3) + ZBF3(g) <:> BBC:le (g) Kr; = 7 KP: [Bitch]? : £311. .-_ 0.023% [Ecglljgps] (Cid (Loo) (9': [801313 2: (acacia. 1-. 0307. [BeifllBél (qm’qfl b) Determine the equilibrium constant for the reaction: BCl3(g) + BF3(g) <=> BFClg(g) + BCIF; (g) Kn" = ? C) Explain briefly why knowing KP" adds nothing to what you knew in part a). KP" :\3/ KPKP" :. \3/@.023‘ill0mlll 1 0,16 5. You are a member of a research team of chemists discussing plans to operate an ammonia processing plant: N2(g) + 31-13(g) c:> 2NH3(g) a) The plant operates at close to 700K, at which K1, = 1.00 x 10‘4 for the reaction. The synthesis employs the stoichiometric 1:3 ratio of N2:H2. At equilibrium, the partial pressure of NH; IS 500 atm. Calculate the partial pressures of each reactant, and the initial and equilibrium PM. My”; :3 2W3 ini‘i' Pfixim) X 39‘ 0 cs; (aim) was -75 so x—ZS gar-7S 50 P1. 1.. UHZ=SO Pu; P»: (math-703 'L (“Sitar—m3 -.= glow!) 3 O (V'ZSVSYfir-zs) -= 2:50;! 5 1 av Grasp! = 245959510) 9.24m M2541] Chum/05' ' =3/,O b) One mcm 5; E e team suggests that since the partial pressure of H2 is cubed in the reaction quotient, the plant could produce the same amount of NH; if the reactants were in a 1:6 ratio of N31H2, and could do so at a lcwer pressure, thereby cutting operating costs. Calculate the partial pressure of each reactant and the initial and final Pm. under these conditions, assuming an unchanged equilibrium partial pressure of 50.0 atm for NH3. Is the team member’s argument valid? ihiiphiw) "n‘ Lac 0 PM -: SC “28:31a‘i‘w‘ Ir he," 3(50'75‘ 73‘4"” : 2ISOA/oj '3 4% PM.» =- Ll X =21“: aim i’m; -- Hvao = m as“ KP : : 00310“? prESSdlfii"? 'mjl kingfidz WIS HOT ’ 'T is 9312 5 41-»; are DVQVGL fi ...
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This note was uploaded on 05/18/2008 for the course CHEM 2080 taught by Professor Davis,f during the Spring '07 term at Cornell University (Engineering School).

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Answer_Key_for_PS5 - Chem 208‘ Spring 2007 Problem Set 5 Due Fri Mar 9 at 2:00PM Name Lab TA Name Lab Day Suggested Additional Problems Chapter

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