2004_2_I_HSLee_answer

2004_2_I_HSLee_answer - (a) (578) Cng— 0113—9]...

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Unformatted text preview: (a) (578) Cng— 0113—9] resonance form°fl E11125} Lewis dot diagram—‘53.: 11117459.. 5:9 (5.9 c9 0 G.) _ /“ e. /‘ ;-y#(; e» Qtfl H a *0\ ~ \\ ‘ - p.‘@ \Q‘e (b) (5%) 502012 em $59:— VSEPR 01%011 Eflfiw ofléfiwg. 0 91:7’ gnu w O// ‘12 ‘ (alidafied JekaAPCIYQQ‘G—J r we inflame» 1 4‘4 wjmww -> s ELL” (0) (57S)C1F3 13-7494 $.75}:— VSEPR 01%01] 37% E301 OWE—ERMA. F ‘ :y \ a N ’4 WET—02‘; V 9‘ / (d 951%! T F #3 a); gs- (d) (573,) Fe2(so4)3 {aha} 7i 5:35:91 1&5}? (oxidation number}:— ENfiN-‘x’m T3 +6 *2 FM 8 0‘93 *3 *3 Eli}. Zn(s) + 2H+(aq) —> Zn2+ (aq) + H2(g) E'l%°1 E‘rlr 3'? °F°d°1 El? iE—flfiié- UH ROPE $¢71fl1<ovg71211a1r1 7mg) 94 $3435 25°C, 1 atmqw 37.40 mL om. won 1% ova—<4 wa— 7415} Am" M ( .931} 5 (NHL) = fl =. Him?) ” “Iii-ix- 1, l!” my 3mg , KT (0‘ 09106 L. whv/K mdf)(;7w may J3 2&1 9” (2“) : M” ‘OKam‘L‘JLp 3 (WW Zn : (IBXlogwbflfififig/mi) = owed \ 3. (10%;!) 1.0M NazSO4 %°—“. 100.0 mL 9+ 1.0M A1(N03)3 %9%‘ 100.0 mL% 419. 13’ A12(SO4)3 7979.0] $853131}. (a) (271%) 0] ‘él-g‘gl net ionic eguation —% 19:743. gmgflol?) + 330121?) -> 291160450) €%€— ‘QUVLUW (b) (47%) $4 10%] 0am—2— ufl law-L: A12(SO4)3 fl = g/mol) (“I m<HQ3+): 7107.1 M» ‘Nsof’? =» NHL.) C MM) = OJ WJXflJ SOT“ Tg We. meera mamasmL ,ro mQfiszOflz) = 3% : 003%?)va 3 (Was; of MAWQB :. (a Maw/mi) (34f2'J63/w41/‘2H 4450 (0 (M3) 0%01 1114 i %9B.91 8042‘ 9+ A13+ 01%q %E1:- 31} 04wa Li D (‘5 W224 uf / S‘o [9072’] =0 M EAQVFJ : A 0166? M 1d .1 4. (107%) “1119] 1437]- N02 9} N209] mixturea‘rE 51% ‘Q—Ti 9,15}. 535% 2. 5‘} €34 0] sampleOHE 51.27% (by mass)—°4 oxygen (O)% §%8}31 gin}. 1:]— % %%°fl fiflfilg. <><4za>No s4 No.04 mm 01%;: Mg. K . L W a :2 nf+3031m o‘roxMJL n” m+v03%(ry') “(>46 avmu‘wv A ‘ F 7' ML (57’ Hr+rog¢n (I. am“ e n, WM“ ox? em 4 N10 ‘ d m My” 0X 0 Z‘JHW) «3419‘»th nvt‘afii/L, (b) (673) $1 mixture {5‘— N02v°4 mole fraction% filfi‘l’fivlfi. Note/f 1man {warm-“:er am we; WA «fiqoh-wck ..,L was; of ox/vgeu 2: 7L LzMAoy-F Chi) C1608) =~ lb +|b'z'/ mu; vfmfhdaow = 9c (“11.3) f u—vc) (LXIfiZ‘c/a) mwrfi"? = 10° - “Mc— +D+w11 mws : (H7 +(6x)+ (ml—Man) =94! +2.7L—u Hm fro X M:____’6'0+’6L_ 72. g Z=a. a“ a 7Lan (a; +2: _.o_5‘/ ?~ _ 51/ 5. (10%) ‘3}%-91 51:3: 9&43‘8VISZ. (a) (5%) H202 (aq) + Mn04' (aq) —> 02 (g) + Mn2+ (aq) (in acidic solution) 9—17)) ‘HLOL —? 04, ffiqijil + [OH’LO MHO - —-7 N u 1 n —-7 :07. + \oflscfi Him. Gar?) mom ——7 0L ' Mun" -—.1 Mm“ + ‘FHLDJ LMnO+~+ 16H30++102 5%» HLO'L + 1})10 ———-9 01,)" LH>0+ I figMan+ aft/W —- 2—H.” un‘ A Mn 01. V+ J’HSOT —-) M‘A t 91 ‘1 LMMO<HA§ WW HzOLW‘ lHto "7 on” ‘8 430+ 3* LLH "HHWHWU chf' + Nat” + J‘Q— *‘7 M“ + '2 ’31 fife-.19) + LMnfiCM‘a) (b) (5%) H2B03_(aq) + A1(s)—> BH4'(aq) + H2A103-(QQ) (in basic solution) ,1. “WW ( Q) 9*?!) H1803— —--,9 W4}, AQ —? HLAR03’ 9W2) Moi—a EH17} mm M, + who ——9 ALAN;- fikrz‘) HLBO§‘+)’HLO -————? ENT‘ + 3H1?) 1‘ J‘Ot‘lfl 9% yea A“ “M “WV—9 Hum; + 4sz £1 filmy +£H‘o +37“, “’7 M1”+7§Hzo +aofl” M+ W++o+r ——> Ham); + 7m.» + 3;; 9* s) 3M0; flww -§ 2% .7 m ~+ fi’ 1 1 Mt + are/gov“ “.9 §H~JH°3‘ +Mto + 2/44 \ maeoaaa) + who +yoH‘(a$) +7HL0(1)~> zwcfiq Mfikog‘mg) 6. (5%) EH??? A. B 1|:— systemOH/‘i 13-11% oéiflr %E9‘rfl filling 1JrE‘r‘ifl 1311335019. 01‘:— system—g] heat capacityfl- E1 E7}? A a) material B Heat absorbed per gram of Temperature 7. (10%) Diborane (Bsz) gas-E i731 odii 4%35}. OWE Zrz‘oifl data'E- 4—8- 3}04 diboranefl standard enthalpy of formation AH°f[B2H5(g)]% $814451. (Hintl AH°f[H20(g)] = ‘242 kJ/mol) 2 13(3) + 3/2 02(3) "" B203(S) AHO = "1273 K] B2H6(g) + 3 02(8') —’ B203(S) + 3 H20(g) AHO = K] #30) + god?) “Whosm 4H”: 423-; kg“ 5L0; (3) + 3H7/ch) ——a Bzmwd)+3ol,r6) 111" = Mgr/C3. *FVI’M CHL(9) + c} OL(D) —9 H209) OH“: ~24; #3“) 77m» + %0-£2r~> wow <1H=€2+1Wa~ 8. (103g) UHELHCHQ 7L)»:— ‘EEE 4%}1,‘ awauo atmfi‘sww alga—:— 194317} 915}. 0] E‘QEMPH filamc (250°C, 1.0 atm)7]- 2m {£5401 13:} *3? go] :31?- ZflEQ @LH‘E'V] 94x33} (300m3)% 10.0°C°1V‘1 25.00Ci HF‘HE fl] éfioiflq‘fi, OWE 4-8-13. “HEWVIQ §%*% :IL5P‘13. %7](air)-'E 01%71ifla‘r 7}7§3}31, molar heat capacity? Cv(air)=20.78 J/Kmol 0111}. @8136 14%94 data% *}%3}1~19_. AH°f[C02(g)] = —393.5 kJ/mol AHOf[HZO(1)] = —286.0 kJ/mol AH°f[CH4(g)] = “75.0 kJ/mol (Hint: U11%(CH4(g))% 0296,39} EMS—"171% COg(g)9Jr H2000] fifiiflufl 0mm) floug) ——? coda) + 2m (0) .@ 4W“ = (AH; [(049)] + zaHfCHLmQH) — @chcmraflmg% : (473$ + Lxcvzfiwfl -—(—ar\o) = $704“ krwg —-‘§3 04(W)=fl —- ("°“M)QWXIOBL—) /( ‘ _l___m_v_w,_w.......w~;_m “um—um—wwm-w-mm : l 2 [I ma RT («.03 1% :qifily‘c) (MBJW‘E) *(7 '4@ had” +1 L227 HMJfM£4 mm bmiwmf)% : MgvdTrJ—afi : 019/042 m) KC—Kfio—hfiu) :éllozclx/od] 1 .02 X/03/< F y w WLW/ ) mm = fli’iflii‘i 3L ao;0_:kg-/W( R 74r/7WXJQ Q’Wmc; of me/FAWVCCI’W) : ({4f/7m01) C/6‘Oé/MJ) = f1}? E 5 $1 zéfi‘é‘fi: 01%5}°4 nitrogenfl phase diagram% :Lfljl $4 78%:2: EARN] 9.. Z} %°fl/‘19] €51.91 ‘QET‘E N2(s) = 1.03 g cm’3 , N2(!) = 0.808 g cm‘30151r. yoSv'J‘Vi g/q/L‘e/ W Jwrwfi 10. (10%) At 25°C, some benzene is added to a sample of gaseous methane (CH4) at 1.0 atm pressure in a closed vessel and the vessel is shaken until as much methane as possible dissolves. Then 1.00 kg of the solution is removed and boiled to expel the methane, yielding a volume of 0.510 L at 0°C and 1.00 atm. Determine the Henry’s law constant for methane in benzene. (Alba-meme: 78.114 g/mol) om, Wm 6M 0.1‘JOL 3M 4 inf; QA‘i‘M)(0‘/HOL) mud-1106 NM— )(zisk) m1 ‘ICV I at DLLODF mask 4% MUM) = “c6 q WW. A7311 Mae/MMGJ via-41k-.. fimiflwiw (ital bwLms‘if’ “ta/(“EL {1.444 MI 4:1 46 ...
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2004_2_I_HSLee_answer - (a) (578) Cng— 0113—9]...

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