# ENES102_S08_Ex2_Answers - 2 P GF = 8.078 kip(C P CF = 4.039...

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Answer Key for Old Exam Problems - Exam #2 Internal Loading Problems : 1) P = 187.5 N V = 145.6 N M = 59.03 N-m 2) A x = 0 A y = 100 kN B y = 60 kN P = 0 V = 20 kN M = 140 kN-m 3) A x = 1.5 kN A y = 4.467 kN B y = 0.9346 kN P = 1.5 kN V = 3.533 kN M = 6.336 kN-m Axial Loading Problems : 1) σ AB = 4.244 ksi σ AC = 16.98 ksi δ AB = 0.02546 in δ AC = 0.03396 in the lamp moves left d AB = 14.13 × 10 -6 in d AC = 8.49 × 10 -6 in 2) σ AB = 0 σ BC = 5.030 ksi σ CD = 4.158 ksi δ tot = 0.001945 in (decrease) d CD = 72.77 × 10 -6 in (decrease) 3) P max = 218.8 kN normal stress governs 4) P max = 35 kN bar material governs 5) P max = 87.5 kN deflection governs 6) σ max = 10 ksi (C) in B δ tot = 0.01484 in (decrease) s f = 2.00067 in 7) σ max = 8.889 ksi (C) in B δ tot = 0.03463 in (decrease) d f = 4.000485 in Truss Problems : 1) P GF = 4800 lb (C) P CD = 5200 lb (T) P BG = 5123 lb (T) P CG = 4000 lb (C) ZFMs = DF, CF
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Unformatted text preview: 2) P GF = 8.078 kip (C) P CF = 4.039 kip (C) P CD = 7.75 kip (T) P IG = 5.924 kip (C) P CG = 1.4 kip (T) ZFMs = BI, DF 3) P EF = 31.55 kN (C) P EP = 2.795 kN (T) P LK = 25 kN (T) P GK = 2.795 kN (C) P KJ = 27.5 kN (T) ZFMs = BN, CN, FP, GP, HJ 4) P CD = 1193 lb (C) P CK = 471.4 lb (C) P LK = 2200 lb (T) P BC = 1565 lb (C) P BL = 1118 lb (C) ZFMs = BM, EJ, FH, FJ 5) P CD = 3 kip (T) P CF = 12.5 kip (C) P GF = 4.5 kip (T) ZFM = CG 6) P BC = 5 kN (T) P BE = 21.21 kN (T) P EF = 25 kN (C) ZFM = BF 7) P AK = 113.1 kN (C) P AJ = 20 kN (C) P GF = 140 kN (C) P GM = 141.4 kN (T) P LM = 40 kN (T) ZFMs = HK, GL, FM, DO (obvious) + BO (not obvious) 8) P AB = 63.25 kip (C) P AM = 155 kip (C) P CD = 18.75 kip (T) P CJ = 31.25 kip (T) P KJ = 97.5 kip (C) ZFMs = BL, EI, FG, GH (obvious) + HF (not obvious)...
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## This note was uploaded on 05/19/2008 for the course ENES 102 taught by Professor Biegel during the Spring '07 term at Maryland.

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