EE110_W08_Quiz 2 Solutions

EE110_W08_Quiz 2 Solutions - j j j j j j j j j j ∈ →...

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Solution for Quiz 2: Q1 has Vth = 0 (the equivalent is simple resistor) Q2 solution is below: 2H 2, 1F 1 Let 1 0 A 2V 0.5 1 1 2 (1 1)( 1) 1 1 1 0 1 1 1 0.5 0.5 1 1 1 1 1 Now 0.5 S 2 , 0.5 S 2 H 2 L c in L in in in j j j j
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Unformatted text preview: j j j j j j j j j j ∈ → → − = ∠ ° ∴ = ∴ = + = + ∴ = + + − = + ∠ ° − ∴ = = = − + − → Ω − = → I V I I V V V V...
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This note was uploaded on 03/06/2008 for the course EE 110 taught by Professor Gupta during the Winter '08 term at UCLA.

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