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Unformatted text preview: line representation of the electric field above is ext E r ext E r F r F r q > 0 q < 0 Imagine that, instead of a point particle, the charge > q were to be distributed uniformly on the surface of a spherical shell. By symmetry, the field outside the shell must be the same as that of a point charge, as shown below. The field is zero everywhere inside the shell. Therefore, the magnitude of the field due the charged spherical shell has a discrete jump at the surface of the shell (see below) Since the electric field obeys the superposition principle, you can use the above discussion about field due to a charged spherical shell to describe a charged solid sphere. To do so, represent the solid sphere as a sequence of concentric spherical shells. To find the total field at any one point, simply add the values of the field due to each of the concentric shells....
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