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quiz4_sol

# quiz4_sol - The Pauli exclusion principle states that no...

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1 Question 1 Calculate the energy carried by a photon of frequency 1 . 0 × 10 15 Hz ( h = 6 . 6 × 10 - 34 J · s ). E photon = hf = 6 . 6 × 10 - 34 J · s × 1 . 0 × 10 15 Hz = 6 . 6 × 10 - 19 J 2 Question 2 What is the momentum of an electron whose energy is 1000eV? What is the de Broglie wavelength? (1 eV = 1 . 6 × 10 - 19 J ) Mass of the electron, m e - = 9 × 10 - 31 kg . E e = p 2 2 m e p e = p 2 m e E e . We need to convert eV to joules(J). E e ( J ) = 1000 eV · 1 . 6 × 10 - 19 J eV = 1 . 6 × 10 - 16 J p e = p 2 * 9 . 0 × 10 - 31 kg · 1 . 6 × 10 - 16 J = 1 . 7 × 10 - 23 kg m s . Now we use the de Broglie relation to find λ e , λ e = h p e = 6 . 6 × 10 - 34 J · s 1 . 7 × 10 - 23 kg m s = 3 . 9 × 10 - 11 m = 39 pm = 0 . 039 nm. 3 Question 3 State the Pauli exclusion priciple.
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Unformatted text preview: The Pauli exclusion principle states that no two fermions can exist in the same quantum state . In the case of the atom, no two electrons can share the same 4 quantum numbers . Examples of fermions are, • electrons • protons • quarks All fermions share the same property of 1 2 interger spin(interges being 1 , 2 , 3 ... so on. Neutrons are not fermions since they do not have 1 2 interger spin. 1...
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