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Unformatted text preview: 2 . 4. From Ampere’s law we have the result that B= µ I/(2 π r). Solve this expression for the current. Remember that 1G = 10-4 T. 5. Use Ampere’s Law. The current enclosed is 1A out of the page. If you us the right hand rule you find that along the y axis, outside of the loop the field is pointing in the negative x direction. The answer is -2.5*10-6 T. Note that the problem said to pick the closest answer. The closest answer is -6*10-6 T. 6. Remember that F = ILB (where B is the field perpendicular to the direction of the current flow). In this case the perpendicular component of the B field is simply the y component. L = 22N/(7T*2A) = 1.57m....
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This note was uploaded on 05/22/2008 for the course PHYS 2b taught by Professor Schuller during the Spring '08 term at UCSD.
- Spring '08