Quiz 8 solution
Test for convergence or divergence.
Please be clear about what test you are using and how you
are using it.
1.
2
2
ln
n
n
n
∞
=
∑
Compare to
3
2
2
1
n
n
∞
=
∑
.
2
11
22
3
2
ln
1
ln
2
lim
lim
lim
lim
0
1
1
2
nn
n
n
n
n
n
n
→∞
→∞
→∞
−
==
=
1
2
=
The series converges by the limit comparison test.
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 Spring '07
 Wei
 Calculus, Mathematical Series, Mathematical analysis, Convergence tests

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