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hw 2 - shah(rps587 Homework 2 mcdevitt(52365 This print-out...

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shah (rps587) – Homework 2 – mcdevitt – (52365) 1 This print-out should have 25 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points What is the correct order of decreasing en- ergy? 1. microwaves, visible light, ultraviolet light, x-rays, γ -rays 2. visible light, microwaves, x-rays, γ -rays, ltraviolet light 3. γ -rays, x-rays, ultraviolet light, visible light, microwaves correct 4. visible light, ultraviolet light, microwaves, x-rays, γ -rays 5. microwaves, visible light, x-rays, γ -rays, ltraviolet light Explanation: γ -rays > x-rays > ultraviolet light > visible light > microwaves 002 10.0 points In the visible spectrum blue light is associated with 1. long wavelengths. 2. middle wavelengths. 3. short wavelengths. correct 4. low energy. Explanation: In the visible spectrum, blue light has high energy and short wavelengths. 003 10.0 points Calculate the wavelength of radiation with a frequency of 5 . 1 × 10 14 per second. Correct answer: 5 . 88235 × 10 - 7 meters. Explanation: 004 10.0 points Which of the following statements best sum- marizes the Planck theory of light? 1. Light should not be thought of as parti- cle in nature; rather it always behaves as a wave. 2. Light contains bundles of energy; all col- ors of light have bundles with the same en- ergy. 3. Light is made up of bundles of matter resembling an elephant’s trunk. 4. Light contains bundles of energy; the longer the wavelength of light, the higher the energy of the bundles. 5. Light contains bundles of energy; the shorter the wavelength of light, the higher the energy of the bundles. correct Explanation: 005 10.0 points Derive an equation expressing E in terms of h , c , and λ , given the relationships E = h ν and c = λ ν. 1. E = c λ h 2. E = h λ c 3. None of these 4. E = h c λ 5. E = c h λ 6. E = h ν 7. E = h c λ correct 8. E = λ h c 9. E = h c λ
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shah (rps587) – Homework 2 – mcdevitt – (52365) 2 10. E = 1 h c λ Explanation: c = λ ν ν = c λ Thus E = h ν = h c λ 006 10.0 points What is the frequency of a radio wave with an energy of 3 . 411 × 10 - 24 J/photon? Correct answer: 5 . 1479 × 10 9 Hz. Explanation: E photon = 3 . 411 × 10 - 24 J ν = ? E photon = h ν ν = E photon h = 3 . 411 × 10 - 24 J 6 . 626 × 10 - 34 J · s = 5 . 1479 × 10 9 Hz 007 10.0 points Light behaves like 1. a wave. 2. a particle. 3. both a particle and a wave. correct 4. neither a particle nor a wave. Explanation: Light exhibits wave-particle duality. 008 10.0 points Which of the following provided evidence that the electrons in atoms are arranged in distinct energy levels?
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