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Unformatted text preview: shah (rps587) – HW 2 – Kleinman – (58225) 1 This printout should have 27 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. This HW assignment covers Ch. 2. 001 10.0 points Two ants race across a table 56 cm long. One travels at 4 . 39 cm / s and the other at 3 cm / s. When the first one crosses the finish line, how far behind is the second one? Correct answer: 17 . 7312 cm. Explanation: Let : ℓ = 56 cm , v 1 = 4 . 39 cm / s , and v 2 = 3 cm / s . You first have to compute the time it takes the first (faster) ant to cross the finish line: t = ℓ v 1 . Then you must compute the distance the slower ant covers in that time s 2 = v 2 t = v 2 ℓ v 1 . The slower ant is ℓ s 2 = ℓ v 2 ℓ v 1 = (56 cm) (3 cm / s) (56 cm) (4 . 39 cm / s) = 17 . 7312 cm from the finish line when the faster one crosses it. 002 10.0 points On a drive from your ranch to Austin, you wish to average 64 mph. The distance from your ranch to Austin is 106 miles. However, at 53 miles (half way), you find you have averaged only 48 mph. What average speed must you maintain in the remaining distance in order to have an overall average speed of 64 mph? Correct answer: 96 mph. Explanation: Let t denote the total time, d the total distance, and v the average velocity over the total distance. Let t 1 denote the time over the first half, d 1 the first half distance, and v 1 the average velocity of the first half. Let t 2 denote the time over the second half, d 2 the second half distance, and v 2 the average velocity of the second half. The change in velocity occurs at d 1 , therefore d 2 = d d 1 . (1) Average speed is v ≡ Δ d Δ t = d t . Thus t 1 = d 1 v 1 (2) t = d v . (3) The total time t = t 1 + t 2 , so t 2 = t t 1 = d v d 1 v 1 (4) since d 2 = v 2 t 2 v 2 = d 2 t 2 ≈ 96 mph . Notice that the formula for average velocity when acceleration is constant: v = v 1 + v 2 2 yields: v 2 = 2 v v 1 = 2(64 mph) 48 mph = 80 mph an incorrect answer!!!! Do you know why this formula is incorrect? What is the acceleration at the halfway point? What is the acceler ation over the rest of the distance? Is the acceleration constant? For constant acceler ation v = v + at . The graph of velocity vs time is a straight line. For this problem the graph of velocity vs time is a step function. 003 10.0 points shah (rps587) – HW 2 – Kleinman – (58225) 2 A car travels along a straight stretch of road. It proceeds for 14 . 9 mi at 54 mi / h, then 24 . 6 mi at 46 mi / h, and finally 49 . 4 mi at 33 . 6 mi / h. What is the car’s average velocity during the entire trip? Correct answer: 38 . 975 mi / h. Explanation: The total distance the car traveled is Δ d = d A + d B + d C = 88 . 9 mi The total time the car spent on the road is Δ t = d A v A + d B v B + d C v C = 14 . 9 mi 54 mi / h + 24 . 6 mi 46 mi / h + 49 . 4 mi 33 . 6 mi / h = 2 . 28095 h ....
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This note was uploaded on 04/16/2009 for the course PHY 58225 taught by Professor Klienman during the Spring '09 term at University of Texas at Austin.
 Spring '09
 KLIENMAN

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