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Problem Set 7 Solutions

Problem Set 7 Solutions - Chem 215 Fall 2007 Problem Set 7...

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Unformatted text preview: Chem 215, Fall 2007 Problem Set 7 Due Friday, Oct. 19, 2:00 PM Ch 10: 56, 58, 60, 66, 70, 86, 97, 107 Name: Student TA Name: fl Lab Day: 1. One of the reactions that destroys ozone in the upper atmosphere is: N0(g) + 03(g) <=> N02(g) + 02(g) a) Using data from the appendix in your text, calculate AG0 and K (at 298 K) for this reaction. AG": 436‘},th + Mi: (0;) ’ Mi: (“5) ‘ML’FWl : (51314» ~ Hr: ~1L3uZ) 1:7 “- “HSJHILT‘ -:: 'KTan. ’3' W: ~MO: M.“ a WI b) Calculate AG for the reaction at 298 K under the following conditions: PNO = 1.00 x10'6 atm; P03 = 2.00 x 10'6 atm, PNO2 : 1.00 x 10'7 atm, P02 : 1.00 x 10"3 atm. P POL Aézngo+ KT in no; F210 8’3 _ ‘T ' 81314 Wave/L] heed/”(100141: glow : ~ ) ‘18 (‘1 LT *7 ,. .. “In“ TILT [/Mtwh‘iu '- ‘ [98va + 62,4,qu “lYJ’ b‘o’ Chem 215, Fall 2007 Problem Set 7 Due Friday, Oct. 19, 2:00 PM 2. Carbon monoxide (CO) is toxic because it binds much more strongly to the iron in hemoglobin than does 02. The equilibrium constant for the binding of CO is 210 times that for binding of 02: (heme)F e + 02 c> (heme)Fe-02 K02 (heme)Fe + CO c> (heme)Fe-CO Kco Koo/K02 = 210. Calculate the difference in AGn for the binding of CO and 02 to hemoglobin at 25°C. 0 a L or = - Tm . Q, _ / " 067: /RT A620 .: ~fl‘T’l/1 ch 27 kc” .: 6' 0 ~ 000 [KT A0; ; ~|€Tln KOL :) K02, = 6’ o" a, _o D A K C ”beta/{1r («5012+ 1501),.) ET 5° ~ 0 : /"“_..‘-““" 2 , “IZ— ,zio €~blroLI£T 6 0L ' G c 210 m 00:1: 7+ A 6’09 . ‘ZT In ‘ ‘rz/O : Q_Cf5>g_)(?,31‘l37fl,eg) Ill 3 [33k7/mré 3. Using data from the appendix in your text, calculate AS", AH° and AG0 for the conversion of graphite into diamond. Comment on the spontaneity of this process as a function of temperature. Briefly comment on the fact that diamond forms naturally. 3mm, bS°<O and 5H°>o) am}; M T atwlact‘ , - 4 u- h , 5+ Apt ~ch réfifdtt HGS Md’lun \5 Seon'l‘aru’o 5} 414’ leaj-l 6‘} __’____‘__£___a 6” Clucj‘ perm nu‘j'uralltj) A} W A‘l hall“ P 56 MAL/5+ become M3fihv¢HYCor Chem 215, Fall 2007 Problem Set 7 Due Friday, Oct. 19, 2:00 PM 4. Using the relationships AGD = AH" - TAS" : -RT an, to determine AH" and /\S0 for the autoionization of water, given the following data. You will need to plot the data as appropriate and determine the slope and intercept. _I_ TC’C) TLL Kw in K 0 3.4.4.106 1.14x10"5 'TBV-KH 25 5.355404 1.00 x 10-14 fizzy 35 33;... ,0—3 2.09x 10'14 “3,, 5’0 40 mam-3 2‘92 X 10': ‘3 ,, IL 50 3009x106» 5.47 x 10 P30; 5.7, 3 3.1 3.2 3.3 3.4 3.5 3.6 3.7 1n (10'3 I6 0 0.5 1 1.5 2 2.5 3 3.5 4 1IT (10" K) 5 . .‘. Chem 215, Fall 2007 Problem Set 7 Due Friday, Oct. 19, 2:00 PM 5. Consider the vaporization of a pure liquid: A(liq) <:> A(gas). a) What is the expression for the equilibrium constant Kp for this process? KP: PA b) Rearrange the equation AG0 = AH" — TAS" 2 -RT ln Kp to give an expression for In Kp as a function of the variables T, AH° and A80 (but not AG"). — RTIn K? = A H"~ros ° ,6 C) WP: ~AHf’+_msé: as _ AH RT RT (‘3 RT 0) Substitute your result from part a) into your equation in part b) to obtain an equation that relates the vapor pressure of a liquid, P1, to its temperature T1. Write down a second, nearly identical equation that relates the vapor pressure of the same liquid, P2, to its temperature T2. 0 I P A3,- M n' K RT. In? = M°~ M 2' a RT; (1); Subtract one equation from the other in part c), in an analogous manner to that done in class and in the text on page 442 for K2 and K] at temperatures T2 and T1. You have just derived the famous Clausius-Clapeyron Equation. 0 .0 a =~AJ \ HAL! £an W, m; m , I: {M ‘4. “g n Pl K T; r. e) The normal boiling point of methanol (CH3OH) at 1 atm. is 647°C. Using thermodynamic quantities for methanol given in the appendix of your text, at what temperature will methanol have a vapor ressureoflOOT ? ___, ’V ' 2" p on P 1 laim=7QO Torr A TZ~Z7SJS+LYJ 3’ 2 ”a - _, ,, p 1 ’00 Torr as} Tl : 7 Anni)- 53L); 1 in “worm : "33 FLT/w? .1035‘/r.':r[,l~ a. l] 100 Torr {fluff/mam , 337.8 TL _ , ”7 "4., ,_ .L Z’ow~—L:*‘—L : z _ ‘4 2.4, 0 ’mo‘5 32?; 77 >77 INK r27: ...
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