Problem Set 6 Solutions

Problem Set 6 Solutions - Chem 215 Fall 200 Problem Set 6...

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Unformatted text preview: Chem 215, Fall 200? Problem Set 6 Due Friday, Oct. 12, 2:00 PM Ch 8:71,81,83,93 Name: Ch 10:13, 19, 25, 31, 41, 51 Undergrad TA Name: Lab Day: 1. The Km for Cu(Ol-I)2 is 1.6 x ID”. The complex Cu(NI-I3)42+ is produced by mixing Cu2+ with ammonia: (31.12%an + 4NH3 (aq) <3 CquH3)42+ (aq) K = 1.0 x 10” a) Calculate the equilibrium constant for the following reaction: Cu(Ol-l)2 (s) + 41le3 (aq) c) Cu(NH3)42+ (aq)+ 201-1‘ (aq) ..—-. 2.1— : ”/7 CU{0HiL(g)‘_'*—b C“ (Ge) 1‘ ZOHQ?) (,7, [fix/0 _. __'x 1+ 1 (.3 Cali“) 1‘9”“; (41) “L—H CL! @693; K '— /.0K /0 .._——-—--——-——"—‘——"——'—_‘—fi_““- C(J{0H)L(YJ 4 9/11/1434“) “Ea—A CUKUH3)¥H+ 205;» KEM’C/f‘ b) Calculate the solubility (in mol/L) of Cu(0H)2 in 3.0 M NH3 (aq). //l +AI'J— fraA/emf WC ”1V5"! ”memle/ 7LAQ'7I 0”"- {I 4A0 frat/me] from Madison 010 M1343 a: 4: {nut—j Commu" {0" e‘FEJ—L; FA (Lu?) ”#5 + #3,0 =___—-3 ”#Y'F'I‘O’I’ -- ,._ x- eflnh) 3.0»): r 7- 2. 5‘ ,5: gL=/.h/o”f:;> x = fW/U' 3,¢1')C 5'0 x- 73x/03 gfofi'j 24 ... / '1’— 3.0 7.3x/o*3 {It CA7 __.v__/; 5 2...? 30—51; 5 7.3x/a +2; 1 [Cu/””3)7LjZO#-3L W : /. é tit/0' ( £1,433?“ [3.0 4m)“ Ayn/me 45<<3L0 M" 3") 7'3””,0’3 (3V8): /_ (“K/o” é- (3.0)‘1r I’ 9’53: (3, off/4M0") 953:- /,2‘?x/0" 7 S ; (Logic) A : ' s . :5 OJ}? leocL. H3 Noam) 012's; )3; ”00,70th ' 91$ _ . ,3 23‘ :- 2{oom)¢r 0.0635" =1) Mx/W‘l/ ' ' 0" .9690 0.0438 W OUf CK‘CUIGXL-J Valve 0‘? 5": 0-03)? w} in 6({0{.’ S’IflC‘e 0A9- ng quumf$wf l ‘— {om our“ €51 m GCI‘UAJWIO r'\ . 5 —__ LLHOFL (“3,0 *‘fsfi h {3H5 (7.3X10b7’1'253?’ _. , , .- 4 ‘\ o. 0%) ”do RHS. 8.. (mm “2374201026 6‘0‘93‘4’ S": (0. 07 1 13" swim 5: 0.026 Ma 2H5 3': Law“) 291W :chSL. '5‘: O- 01—? S M'”‘””“‘" 0 .023 if M \ 7' OIOC-S 'flw; fowl =- 7-3x/0—31'Z(5-°2~5) : O'OC’BM‘ [U143] = 3.0 — L+(o.02.3) = 2.??6/‘7. D065 #e, adobe] [0H1 ‘From CK{OH)7_?QL6-fiorccin_&% $9464 [’3 44-2 bafich‘b 0%: U143? 4 _. AM + H2,O ~film}, +024 3 M (m) 2.356 0-043»; W ZEW'X A: 0.0L3Hc .OL ’5 ,- . M 1 MEX/0 5 2 4"?va A‘SYUM x441??? xcc gang 0‘) {00(37- ; ”35/05 _) A 7, gig/0A” 2.95; cam-Wm: 5'25“” 7,: M? m = /§/% 0.0é3 fly; so/A.‘H.7 55' 0.028n7r6u (.. Chem 215, Fall 2007 Problem Set 6 Due Friday, Oct. 12, 2:00 PM 2. Sand is primarily silica, SiOz. It can react with water to form silicic acid: Si02(s) + 2H20(l) a H4Si04(aq) K = 2 x 10'3 Silicic acid is a weak acid: H4Si04(aq) + H20 a H38i04' (aq) + H30+ (aq) pKa = 9.46 a) Will silica be more soluble in an acidic or basic solution? Why? LL “1;” be more SDIQLIE in basic Spin/Lidia. Since, +L-L OH, in JrL—L 5:152. Soiu'i'iom I-«J‘Ii-i FCGC'I' WI'I'A (and Coax-mad.) ”30$: \ l . . . d 0H,. CLC‘COt—oii +0 Le CKK‘iElICKJ Fr'Ac-t? [1.) Increase will 5:??? +54 aquillarfium' "in +I~e. r75k+. (Acidic. Condidibns would Slug ‘He Qatar» '41: 44-0. IQH) ' b) Calculate the molar solubility (in moliL) of silica at a pH of 7.0 and a pH Elf-10.0. "3 't. _. From -H~.e Silurs‘i' efim ‘- K= [H9309] 'Z'KIO H From m 3.2mm! eq‘m KJ [Hassoflt H50Q:3.H1xlo"“w [Hf-5; O43 Usmj @0301}: leofiM owl Iago-*1: 1.0xlonM{PH=7a)/ [HBSIOq—Q=WM H50$C<= SD 1 W3) Lox/0'7 [ass-0&3 = 7x/0'6/‘7 Ce? film-A717 = 54390;; +[#ys;_owj Chem 215, Fall 2007 Problem Set 6 Due Friday, Oct. 12, 2:00 PM 3. The following data was obtained from a reference book (25°C). You may assume that AH} and So do not depend on the temperature: Molecule AHOf AGOf S0 (kamol) (kamol) meol-K Hg0(s) -90.83 -58.539 70.29 Hg(g) 61.32 31.820 174.96 Hg(l) 0 0 76.02 02(g) 0 0 205.14 a) Using this data, calculate AG for the decomposition of 2 moles of mercuric oxide Hg0(s) at 100°C: 2 Hgoo) a 2 Hal) + 02(g) \ as“: limelhgoflwk) +ng](2c~r.NJ/meel "ZmrdW-Zwmfi 2211.1. The DH: (Zmd'e)( GET/Mia} +ere)(6LT/mre) *2mr€("90.3‘3 icI/mfl) : ISM-la KY oc=m°~ 113$“ 2-. mun {373,13t) {mp/K) “- WILLIE?“ $082.15.? = 100.8 I: a ' b) For what temperature range (in 0C) is the decomposition of mercuric oxide, Hg0(s), spontaneous? For did” T2.) (sew? l O gergHi-msc'co? :) ‘1‘ = 9.5 z. Irka : 357 ea’ ‘55 cartel-376 K Fe- Qam .mW in WWW“ WTfls’K lie. +61%?» SGQOC .— c) Using the above data, estimate the normal boiling point of mercury. AH; = + c, [.32 lav/me?- f‘ _ {35°ka = . ‘3 c M Mme gt».- Md Ni "IDS 3 O Chem 215, Fall 200';l Problem Set 6 Due Friday, Oct. 12, 2:00 PM 4. Consider the two reactions for the production of ethanol: 1. C2H4(g) + H20(g) —-> CH3CH20HU) ii. C2H6(g) + H30(g) —-> CH3CH20H (l) + H; (g) Since CgHfi is much less expensive than C2H4, it has been suggested that a new plant be constructed employing reaction ii, rather than i. From a thermodynamic standpoint, comment on whether or not these reactions are viable methods for production of ethanol. gr i) A H”: #27") .7 ”57-2; -ZW.FJ 123' ‘5 -—?;=.2_ :3“ 53°: /£./-[z{'i +/J" s} T/zg‘ 3 -—'2.L£'7'J'/,( l: ’ AG :‘o w) 7‘ - 5H6 — $82 W037— ” 91"“). ., "‘ 97'—— = =360K_ EgMo-TAS:0 Ar ‘25; 7.774(- m ream/{M 55 Sfflfl+€neflVJ Ml 7(390K5V/4545 k5) bH°= —27§’-—(-—8‘f.7 —2.vz) -= +v9h3‘ as°=l73l H“ e {azarnsfl-I/k =—/sz/z. Mm £36 =oH°-—7—45“>o Br «I! “T- 72;, Name-M 55 I flagpon'lnneou} # a II 1cm? ”Avg; . U07" weste— 5. Suppose that 50.0 g of liquid water initially at 2m, is mixed with 65.0 g of liquid water initially at 50.0 °C. The process is carried out at constant atmospheric preSSure in a thermally insulated vessel. Calculate ASS” and ASuniv for the process. ”71x $0.09 #,,O @ 20°C (2573/5789 505% 5510? 5&0 @Wtézizrcl :10. 9A0}, 46. aC‘cJD/ ”259+ 5M 57;”. "f ”7694; 5cm! 437;“, = o @506) {gfllm—ma) web's-as) (sea) {7; ~20°cl .. o QSTP- 3250+- 5'07“; -10du :0 Algeria? n 1;: IWTPPL‘ZSO :0 c ”Q73 legit PEI TF' .._.' :{2é501 3996C =3l0-ll K . rue-9 hm?!) ”£31: For we; Cf:<%.I3w.11_‘c_)(is.o_l)t753§oc -— llfTTT/K‘ UfiMl e1!” defined “.‘A QthSSZ 3 “we M A391“; ASlm'l'll—ASMKJ as = no lo Ir- = 0:88?“ “vi F TE 31mm U ‘3 H5“: O : "' loud = llJ‘i'J/K. 501mg: 05317:: snags”; ...
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