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Problem Set 9 Solutions

Problem Set 9 Solutions - Chem 215 Fall 200 Problem Set 9...

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Unformatted text preview: Chem 215, Fall 200? Problem Set 9 Due Fri. Nov. 2 at 2:00PM Name: Undergraduate TA Name: Lab Day: Suggested Additional Problems: Chapter 4: 5?, 63 Chapter 15: 17, 19,23, 25, 29, 31, 35, 37, 39 I. Triiodidc ions are generated in solution by reaction of iodate ions with iodide ions in acidic solution: 103' (8(1) + I ' (aft) -> 13' (3(1) Triiodide ions can be titrated with a sodium thiosulfate (N 2128203) solution. The products are iodide ion and tetrathionate ion, 840521 a) Balance the equation for the reaction of 103' with I'. (a. c, ”(3: fig; I o; (2'?) llo€+ |8H++3Io3fl~a Ia" + 9H; 0 ——v 32: 3,93%) 8’ Effie I‘+2e 4“" 1’3 ++2¢IIC+SIO ‘——) 913 at 9:42 0C“ b) A sample of 0.601%?Jof potassiiuii iodate wasg 1§dolved in wgté’r‘. Hydrochloric acid and solid potassium iodide were then added in excess. What is the minimum mass of solid K1 and the minimum volume of 3.00 M HCl required to convert all of the 103' ions to 13' i0ns? (holes K103 2 o'ng.‘ ; 2. Stealohgmrf. Zf‘f.05/h..l' ”Wolf! KI Pails! : (2.310310%) (3) =3 3 grams KI refi‘dz (2.3l02n’f0_3)(5‘)haol€j X JLLO /IM"'F ; 3-732,, K1. Mal-9J5 HCI r91‘cl :EZ’SHO’E :0"? l{£)]m.le5 3 c 1" Vole Hot n.- ‘4: {galaxm’flt’mu = 9. £22: 0 c) Write and balance the equation for the reaction of $203} with 13' in acidic solution. Tfl+ZéF-+ 31*" or” ___a f 7. slofg—a SI, Os "+Ze f z-a d) A 25.00 mL sample of a 0.0100M solution of K103 is reacted with an excess of K]. It requires 32.04 mL of N333203 solution to titratc the 13' ions present. What is the molarity of the N323203 solution? -9 moles K303 = 25.00xl6'3t. )c 091%”? _-_- 250x10 awe WC” 1: Paw: Mamas-1%“) = 3(25096/0‘7 =7-W/0' /' 50X {CHEM/e)- 0. ova/Vt Y 3 / - [.SOK/O ma 6'} m ‘l'L‘ j M S O - _. 2. Consider the base-catalyzed reaction OCl' (aq) + I' (aq) —> OI'(aq) + Cl' (aq) Use the following initial-rate data to determine the rate law and rate constant, 129., determine n, m, p, and k where: Rate = 1c[ocn"[1'1“‘[OH']" 001 M 1' M 0H Rate 1.62 x 10'3 1.62 x 10'3 0.52 3.06 x 10“ 1.62 x 10'3 2.33 x 10'3 0.52 5.44 x 10" 2.71 x 10'3 1.62 x 10'3 0.84 3.16 x 10'4 1.62 x 10‘3 2.88 x 10‘3 0.91 3.11 x 10“ .3 I" ‘(4' - gmhmw M] M .-_ 561:;me 3 me®a6d®o .812: ('1’.— [-UZKIUA'H) f m 2.86)”: 5.111.; 7—6-5 5.0L 1129““: 1:118 F‘w®‘~'® 3:1 )41Mfimmé) (0.925114) 311 (0:: RI MW"?( (11/112111 WVM’M Wm (105196“le 1:15? 6. $11 ?luj’f}§- 16.7001— :— 24%53‘:—1.oo \ oi : -1 } Fflr~®RN® R3 __ JIXIU_3h n 03W?!“- 2:; H. [0.7 13' EMI-mm‘gh)“ 100’ 411‘ (Mm) " 3oLMu‘ r 2.11 11 , fly; (fly) LEE, _ 3.0L. 056 K. 4 Z W n-ra'l F0546): 3 ooxlfi‘fl fiWminJDameiflfidflfl 1:: GO (a s _ _.___ 3. When heated, tetrafluoroethylene dimerizes to form octafluorocyclobutane: CZF; (g) —) V2 Cilia-(gi— '- At 488K, the following data was collected. lnfC‘zj—"J [c2120 (M) [El—£3 Time (s) — 2.303 0.100 /o.o 0 _ g m 0.030 {2. S 56 _ 0.060 /c.7 150 123283 0.040 2 5', o 335 _ 3: 307 0.030 3 3, 3 520 Analyze the results by plotting the data as appropriate for zero—, first-, and second— order behavior. 0 100 200 300 400 500 600 Time (s) 0 100 200 300 400 500 600 ‘l 00 200 300 400 500 600 Time (s) Time (3) a) Determine the rate constant k and write the rate law expression for this reaction. _ -l flaw {Cg—ES «r 7" £5 hm.“- 54,192,:(3iiofolh a}; :. -—0l F‘r ___ 1 __ _ ._ kfcafir] : 953/0 Zn ’5 ’ b) How long will itt ntil the reaction is 90% completed? : k _ [new 0:00., comPieJeog [A]: 01017130. PM a yet-Ma wash (1 A J— .-. —L + 11+ ’0 = w Fee ,a , Bot [/90 £6 q 1:»). I<[ qt ___L. : —--L- + 7001 fia‘ism'iflramam) O-IZ-fil, [Alf .- ._L : 10" l c 9 ) :45 ZOOOSec . k-éqoq.: 0.[Aja [43¢ [4'30 (it The decomposition of dinitrogen pentoxide (N205 ) is a first order process: ““2051 N20: (3) —> 2 N02 (g) + '& Oztg) ‘ dt = kobs [N205] At room temperature (298.1510, the rate constant for this process is km = 3.5 x 10'5 s". A sample of 1.00 g or guacuua N205 in Put into an evacuated 15.0 L final: at 309.1516. The molar mass of NaO( is t08.0 glmole ii) What is the initial partial pressure. in mm Hg, of Ngosig)? moms ULOfHJ£2£fL c: (yoofiérmld logos/mg P=- “QT :(O-Oo‘i?m«ie5! (morzom m” d‘fintSL-l 0 015 rm V __'_“-_M : 1 q Ig‘oL H b} What is the partial pressure,in mm Hg, ofN205(g) after3.0 hours? _. [/fm Hf 1;: 3L00;){ am) :10 8065- L.- 3' ’ _, _ k‘f _ id: c) What is the total gas pressure, in mm Hg. in the container after 3.0 hours? NLogm —v 2 M07, +5: 0?— imei ll-S 0 0 Ed W53 PF: PE, -3f7+'7.'~i+|.95 CM '3"? = tI.§-rs.5'5”=h.om d} What is the half life (tug) of the reaction in hours? Recall that the half life is the time required for the H? . initial concentration to decrease to half of the initial concentration. REAL: ln [A30 h "-5 _ o E H37 Vile, Era-t" L2? 110 1 ln Z- ] a A - .: __,__.__.— :__ _.._.——-—- = S' \n % * '4?qu 4:17. k. 3311106 i300 E , in Jerri-Ia, *1; 53M ...
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