Lecture 7 - Monday: Finishing Ch. 6 1 CO(g) + 2H2 (g) CH3OH...

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1 Monday: Finishing Ch. 6
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2 CO(g) + 2H 2 (g) CH 3 OH (g) For ANY initial conditions, after reaching equilibrium at t e : [ ] [] [] 5 . 14 H CO OH H C K 2 2 3 = CO H 2 CH 3 OH CO H 2 CH 3 OH CO H 2 CH 3 OH
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3 For the generalized reaction: aA + bB +…. . gG +hH+…. The equilibrium constant in terms of concentration (K) is: Rules for Handling Equilibrium Constants: 1. When we reverse an equation, we invert the value of K. 2. When we multiply the coefficients of balanced equation by a constant, we raise K to the corresponding power. 3. When we divide the coefficients of a balanced equation by a constant, (e.g., 2) we take the corresponding root of K (e.g., square root). [ ] [ ] [] [ ] ..... B A .... H G K b a h g = Given: N 2 (g) + ½ O 2 (g) N 2 O(g) K = 2.7 x10 -18 N 2 O 4 (g) 2NO 2 (g) K = 4.6 x10 -3 ½ N 2 (g) + O 2 (g) NO 2 (g) K = 4.1 x10 -9 Calc. Kfor: 2N 2 O (g)+ 3O 2 (g) 2N 2 O 4 (g )
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4 Activities make Equilibrium Constants Dimensionless For the generalized reaction:
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This note was uploaded on 04/16/2009 for the course CHEM 2150 taught by Professor Chirik,p during the Fall '08 term at Cornell University (Engineering School).

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Lecture 7 - Monday: Finishing Ch. 6 1 CO(g) + 2H2 (g) CH3OH...

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