Thermodynamics Notes24

Thermodynamics Notes24 - ME 311 THERMODYNAMICS S. Masutani...

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Unformatted text preview: ME 311 THERMODYNAMICS S. Masutani FALL 2007 CHAPTER 9 (continued) REGENERATION heater turbine regenerator cooler compressor 4 5 6 3 2 1 t W & c W & c Q & H Q & R Q & Process Representation 1 2 4 5 p s T, h p 6 3 h 5 , T 5 Q H m Q Q H H & & Observe that ) ( ) ( ) ( ) ( 6 5 2 3 6 5 2 3 h h h h h h m h h m = = & & ) ( ) ( ) ( 6 5 2 3 6 5 2 3 T T T T T T C T T C p p = = for an adiabatic regenerator if C p = constant For a counterflow regenerator, it is theoretically possible to heat the gas from T 2 to T 5 (if C p = constant). Systems have been built in which >95% regeneration has been achieved. 1 ME 311 THERMODYNAMICS S. Masutani FALL 2007 Example For the previous open Brayton cycle with c = 0.85 and t = 0.87: BWR = 0.735 and cycle = 0.178 The temperature leaving the turbine is 571 K; the temperature leaving the compressor is 460 K. . If we obtain 85% of this maximum temperature rise, then the temperature of the gas leaving the regenerator upstream of the heater is 460 + 0.85(111) = 554 K temperature of the gas leaving the regenerator upstream of the heater is 460 + 0....
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Thermodynamics Notes24 - ME 311 THERMODYNAMICS S. Masutani...

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