# hw5-5 - You may only choose the 3 singers from the 20...

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Math 1160 – Section 5.5 Answer Key 2. 5 4. 120 6. 66 8. 20 22. P(6, 2) = 30 ways 24. C(5, 3) = 10 pizzas 26. P(6, 6) = 720 ways 28. C(10, 4) = 210 ways 34. C(8, 5) = 56 ways 40. C(20, 4) = 4845 ways 57. Moe C(9, 2) = 36 candy choices Joe C(7, 3) = 35 candy choices Joe is correct. He has fewer candy choices than Moe. 66. C(20, 3) x C(14,2) = 103,740 ways
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Unformatted text preview: You may only choose the 3 singers from the 20 singers available. You may only choose the 2 comedians from the 14 comedians available. You need 3 singers AND 2 comedians, so multiply the combinations. 79a. C(45, 5) = 1,221,759 tickets 79b. C(100, 4) = 3,921,225 tickets 79c. First lottery 79d. Second lottery Compare the number of outcomes of P(45, 5) to P(100, 4)...
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## This note was uploaded on 05/21/2008 for the course MATH 116 taught by Professor Copeland during the Spring '08 term at Western Michigan.

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