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Unformatted text preview: d by R1 is P = v1 i1 = 150 = 450 W 3 1 The power absorbed by R 2 is P 2 =  v 2i 2 = 150(6) = 900 W
P3.215 We can label the circuit as shown. The subscripts suggest a numbering of the circuit elements. Apply KVL to node the left mesh to get 15 i1 + 25 i1  20 = 0 i1 = 20 = 0.5 A 40 Apply KVL to node the left mesh to get v 2  25 i1 = 0 v 2 = 25 i1 = 25 ( 0.5 ) = 12.5 V Apply KCL to get i m = i 2 . Finally, apply Ohm's law to the 50 resistor to get v 2 12.5 im = i2 = = = 0.25 A 50 50 P4.21 KCL at node 1: v v 4 ...
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This note was uploaded on 03/07/2008 for the course BME 211 taught by Professor Cain during the Winter '07 term at University of Michigan.
 Winter '07
 Cain

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