2 2 kcl at node 1 v v v 1 2 1 1 0 5v v 20 1 2 20 5

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Unformatted text preview: 4 - 2 1 1 2 0= + +i = + + i = -1.5 + i i = 1.5 A 8 6 8 6 v (checked using LNAP 8/13/02) P4.2-2 KCL at node 1: v -v v 1 2 1 + + 1 = 0 5 v - v = -20 1 2 20 5 KCL at node 2: v -v v -v 1 2 2 3 +2= - v + 3 v - 2 v = 40 1 2 3 20 10 KCL at node 3: v -v v 2 3 3 +1 = - 3 v + 5 v = 30 2 3 10 15 Solving gives v1 = 2 V, v2 = 30 V and v3 = 24 V. P4.2-3 KCL at node 1: v -v v 4 - 15 4 1 2 1 + =i i = + = -2 A 1 1 5 20 5 20 KCL at node 2: v -v v -v 1 2 2 3 +i = 2 5 15 4 - 15 15 - 18 i = - + =2A 2 5 15 P4.2-5 Node equat...
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This note was uploaded on 03/07/2008 for the course BME 211 taught by Professor Cain during the Winter '07 term at University of Michigan.

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