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Unformatted text preview: i i i+ += ⇒ = + Eliminating i 1 and i 2 from the supermesh equation: ( 29 ( 29 3 3 3 3 6 2 4 5 8 8 9 24 i i i i+ + = ⇒ = The voltage measured by the meter is: 3 24 3 3 8 V 9 i = = P4.73 Express the controlling current of the dependent source as a function of the mesh current: .06 b a i i =Apply KVL to the right mesh: a a a 100 (0.06 ) 50 (0.06 ) 250 10 mA a i i i i++ = = Finally: o b 50 50(0.06 0.01) 2.5 V v i = == P4.715 Label the node voltages as shown. The controlling currents of the CCCS is expressed as a 28 v i = . The node equations are a a b a 12 28 4 14 v v v v= + + and a b a b 4 14 8 v v v v+ = Solving the node equations gives a 84 V v = and b 72 V v = . Then a 84 3 A 28 28 v i = = = ....
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This note was uploaded on 03/07/2008 for the course BME 211 taught by Professor Cain during the Winter '07 term at University of Michigan.
 Winter '07
 Cain

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