BME211HW5 - Homework#5 Solutions P6.3-1 P6.3-3 The voltages...

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Homework #5 Solutions P6.3-1 P6.3-3 The voltages at the input nodes of an ideal op amp are equal so 2 V a v = - . Apply KCL at node a : ( 29 ( 29 2 12 2 0 30 V 8000 4000 o o v v - - - - + = = - Apply Ohm’s law to the 8 k resistor 2 3.5 mA 8000 o o v i - - = =
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P6.3-5 The voltages at the input nodes of an ideal op amp are equal, so 0 V a v = . Apply KCL at node a : 3 0 12 0 2 10 0 3000 4000 15 V o o v v - - - � � - - - = = - Apply KCL at the output node of the op amp: 0 7.5 mA 6000 3000 o o o o v v i i + + = = P6.3-6 The currents into the inputs of an ideal op amp are zero and the voltages at the input nodes of an ideal op amp are equal so 2.5 V a v = . Apply Ohm’s law to the 4 k resistor: 2.5 0.625 mA 4000 4000 a a v i = = = Apply KCL at node a : 0.625 mA b a i i = = Apply KVL: ( 29 ( 29 3 3 8000 4000 12 10 0.625 10 7.5 V o b a v i i - = + = =
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P6.3-8 The node voltages have been labeled using: 1. The currents into the inputs of an ideal op amp are zero and the voltages at the input nodes of an ideal op amp are equal.
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