BME211HW6

# BME211HW6 - Homework#6 Solutions Ex 7.3-2 a W t W 0 t 0 vi...

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Homework #6 Solutions Ex. 7.3-2 a) b) ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 0 4 4 0 0 4 4 2 0 0 First, 0 0 since 0 0 1 Next, 0 10 2 2 10 2 10 2 2 10 t t t t t vi dt v v t v i dt dt t C t t dt t = + = = = + = = = ° W W W W ( 29 4 1s 2 10 J = 20 kJ = W ( 29 ( 29 2 4 8 100s 2 10 100 2 10 J = 200 MJ = = W Ex 7.4-2 Ex. 7.5-1 ( 29 ( 29 2 2 4 1 1 4 8 0 otherwise L s t d v t i t t dt < < = = - < < and ( 29 ( 29 2 4 2 4 1 8 4 8 0 otherwise R s t t v t i t t t - < < = = - < < so ( 29 ( 29 2 2 2 4 ( ) 7 4 8 0 otherwise L R t t v t v t v t t t - < < = + = - < <

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Ex. 7.7-2 P7.2-8 ( 29 ( 29 ( 29 ( 29 ( 29 2 3 2 3 2 2 2 2 2 1 1 2 10 25 1 2 A 200 10 40 6 10 10 2 10 200 A 200 25 50 25 150 A t t R t t C t t R C t v i e e dv i C e e dt i i i e e e μ μ μ - - - - - - - - = = - = - - = - - = = + = + - = + P7.4-4 Replacing series and parallel capacitors by equivalent capacitors, the circuit can be reduced as follows: Then ( 29 ( 29 ( 29 ( 29 ( 29 8 8 8 1 32 4 cos 3 12sin 3 sin 3 V 21 21 21 7 C d C d i t v t t t t d t d t v = = = - = -
P8.3-2 Here is the circuit before t = 0, when the switch is closed and the circuit is at steady state. The closed switch is modeled as a short circuit.

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