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HW1 Solutions - y2 t ru Basis n:o_l b r lr t b.lrl ft l(s x...

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y2) Basis: t ru n:o b -._l _.,_ rlr tb. lrl ft)'l (s'xlb,) =0.Ia(ffxtb, ) Let A = arca of the Pipe md v = water velocity. The flow rate is (o'),, c =nv =[1.;tv) nl(2 inll (l ft)' 13 Rl60 s 17.48 gal 4l l(12 in)'| s ll pinl I ft 129.37 gal / min| I IPrA-r4 rrr- [ro.on1'zl r I r s' 2t lo4s4 ksl\ s t ln.2 w^l ft 177s.2(ftXtbr) .--::-|---;I = lDr I sec- | = Ifdr t Btul .l'19 ) Q=0.61S ./@Ap)/p assumeholeisopentostnosphere o,=*gfog * zring"..lo.zoru,ol,* | '-ti} I ' r ft' I in' I t r* lr2 inl33.er fr H,ol = 3,579 lbr/ft) ,- o.rori, lu'.ffi=or.e?!!* ' I lb/n'H.oi s=o|, I ']'=l.4rxro'ft' [(4)12l er = (1600x0.6rx3.0r ' ro'lr(zxlsurle.Tl.rz = ls+Sl r.zo l --/ wr. The net units on the right hud sidc of the cqution are , | *t 'l'" mt m-l-il *- Ls I s Conscquently, Lhe formula will nor yicld 80.E mr/s, pmumably in the iomula the g should be g fo u* in the AE systm. G ) t* numbcr of significant figur* to the right of the decimal point is l (from 2 t 0 0m)' :7 i;;";,h. ;um ofi I 5 l I 0 m-should be rounded to 2 I 5 l m' - ^.--,.[o,lrr.l'o".lro',0'nr*',1, 1" s=uo(zml-[;'_Fl-l€]
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=\ 1,35 rr Step l: Theproduct l.3g24isrcundedoffto 1.4 Step 2: Calculate enors.
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