June Key

June Key - Biology 12 June 2001 Provincial Examination...

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016bik - 1 - July 31, 2001 Biology 12 June 2001 Provincial Examination A NSWER K EY / S CORING G UIDE CURRICULUM: Organizers Sub-Organizers 1. Cell Biology 2. Cell Processes and Applications 3. Human Biology A, B, C, D E, F, G, H I, J, K, L, M, N, O, P Part A: Multiple Choice QKC S C O P L O S C O P L O 1. C U 1 1 A1 26. A U 1 3 K1 2. C K 1 1 A1 27. A K 1 3 L1 3. C H 1 1, 2 A2; C1; E1 28. B U 1 3 L1 4. D K 1 1 B1 29. D K 1 3 L7 5. B U 1 1 C1 30. C H 1 3 L8 6. C U 1 1 C1 31. D U 1 3 M2, 8 7. A U 1 1 C2 32. B H 1 3 M3 8. C K 1 1 C7 33. C K 1 3 M7 9. A U 1 1 C10 34. D H 1 3 N4 10. D U 1 1 D3 35. A U 1 3 N4 11. B K 1 1 D5 36. C H 1 3 O1, 2 12. D K 1 2 E1 37. C U 1 3 O2 13. C H 1 2 E1, 2, 4 38. A H 1 3 O2 14. C K 1 2 F1 39. B H 1 3 O2 15. A U 1 2 F1 40. C H 1 3 O2 16. B H 1 2 G6, 3, 2 41. A K 1 3 P1 17. C H 1 2 H6 42. A U 1 3 P1 18. A K 1 3 I1, 2 43. B U 1 3 P1 19. D K 1 3 I1 44. C U 1 3 P6 20. B K 1 3 J1 45. C K 1 3 P7 21. D H 1 3, 2 J2, 7; G6; I7 46. D H 1 3 P5, 6 22. B H 1 3 J8 47. D K 1 3 P7 23. D K 1 3 J9 48. B U 1 3 P8 24. C U 1 3 J11 49. C U 1 3 P9, 10 25. C H 1 3 J12 50. A H 1 3 P10 Multiple Choice = 50 marks
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016bik - 2 - July 31, 2001 Part B: Written Response Q B C S CO PLO 1. 1 U 5 1, 2 D2, 3; F5 2. 2 U 4 2 E1 3. 3 K 4 2 G4, 3, 2, 1 4. 4 U 5 2 H1, 6 5. 5 U 4 3 I1, 2, 4 6. 6 U 4 3 I1, 2, 4, 6, 9 7. 7 H 6 3, 1 J9; L6, 7, 8; B3 8. 8 U 6 3 J7, 9 9. 9 U 7 3 M3 10. 10 K 5 3 O1, 2, 5 Written Response = 50 marks Multiple Choice = 50 (50 questions) Written Response = 50 (10 questions) EXAMINATION TOTAL = 100 marks LEGEND: Q = Question Number B = Score Box Number S = Score K = Keyed Response C = Cognitive Level CO = Curriculum Organizer PLO = Prescribed Learning Outcome
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016bik - 3 - July 31, 2001 PART B: WRITTEN RESPONSE Value: 50 marks Suggested Time: 75 minutes 1. a) Name and describe the process shown below. (4 marks: 1 mark for name; 3 marks for description) xy x y y 1 x 1 + 1 x 1 y Name: • DNA duplication • (DNA) replication either one for 1 mark Description: Unzipping: • The hydrogen bonds between the base pairs break (unzip). • Helicase (enzyme) is involved in breaking hydrogen bonds. Complementary base pairing: • Complementary base pairing occurs. • DNA polymerase acts as a “proof-reader” to ensure that there are no errors in base pairing. 2 new identical strands created: Sugar of one nucleotide joins with the phosphate of the adjacent nucleotide to form the sugar-phosphate backbone. • The end result is the formation of two identical DNA molecules. 1 mark for each part of the process
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016bik - 4 - July 31, 2001 b) How could a virus affect the molecule shown in the diagram above? (1 mark) • It could cause a mutation by addition or deletion. • It could change a proto-oncogene into an oncogene.
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June Key - Biology 12 June 2001 Provincial Examination...

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