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Solution_HW1

# Solution_HW1 - 12.5 A ﬂight train travels at v = 60(1—...

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Unformatted text preview: 12.5. A. ﬂight train travels at v = 60(1— e")ft/s, ' / “there t ts the elnpsed' time in seconds. Determine the distance traveled In three seconds, and-the acceleration at this time. , v {OOH-e“) / 2 I.*‘!V‘FI:60(I—¢")¢ ‘ - 600+ ﬁr: r: l H.113 it A.- l = E x “(9'5 Prob. IZ—ﬁ ' m- a. IAII 12-7. The position of a particle along a straight line is given by .t = (t3 — 9:1 + 15:) ft, where t is in seconds. Determine its maximum acceleration and maximum velo- city during the time interval 0 5 t s 10 s. r=P—9t=+lsr '-u=d—I=3r'—18t+lﬁ d! du_ ' H “*dt_6‘ 18 ‘ I \' .- am,occursatt=103. aw=6(]0)-'18=42W52 Ans vmoccutswhent_=_103 em = 300)1 — 1300) + IS = I35 tits ‘12-“. A motorcycle starts from rest at s =- 0 and m f: a I travels along a straight road with the speed shown by the . , v-t‘grapht Determine the motorcycle‘s acceleration and ' a _ 1v _ o - - A”. T position‘when .t _= 83 and tl.= 12 s. d" - A: = I'M: [-0 - item + (I—4tt5) - 30 1-301! A— Arum: g'.%=:5—5--|mh' Au Ar=Ivk I. _ l I 3 3 . 3-0 I 5(4)“) ”1041(5) + ans-IQ“) - 5(3)“)(95) s-“tn All 12.42. The H graph for a particle moving through an “a‘éét'ric ﬁeld from one plate to another has the shape 'sh‘o'wn iii the figure, when-pf = 0.2 s and 11m = 10 III/s. ' Draw the 's-( Lgnd H graphs for the particle; When .- 1 = i'ﬂslliapbrttiele is at s = 0.5 m. a 34: ,, ii 52 {1 mo<1<€lia 5r; v- Ill)! :: a. -? ¢-—--- 1” . dz- m '_ Mun/p} {:7 I'd.- I'mom ' ' "" 3- 50!, f mar-0.“. -toa f—i 1'. Mil “' Farm: <I<OJI I stun) r v- -loo:+2o i d? 11.3.. -1m 0.5 di- Ill 04 I“ d: n In (-IWI+ Md! 1 -05. {.so:'+NI-L5) J I -ﬂ?+mlfl Whal=0.23. J-lm ﬂ!) _,_— 12-15. Aparﬂnleitmovingllongueti'nighllinesucil thatwhnnitisattheoriginithnsavelneityuf-im/s.“ it begins todacclerateatthcrate at": = ("1.50”) Iii/E. ‘ where u in in unit. data-mine the putinl'e‘s position and - velocity m t -= 2 s. ’u=g=-L5v& . . my: 4.5a: . f L zéﬂbmii 20:sz = —LSl ’ u=(1-—i}.1'5.t}a m1: :1"; = (2-0.7:an . 0.25 mm A.- Ea=£a—o.7sn=d:= £(«3nasmﬂ a .-_—4;—Ls:‘+a.ms:3 «ML; =4(2)»l.5(2)=+o.1875(2)’ - 3.5 in Au‘ 12-22. The aqceleralion of a rocket traveling upward is given by a = (6 + 0.025) m/sz, where s is in meters: Determine the rocket'a velocity when 3 = 2 km and the time needed to reach this altitude. Initially. tr = 0 and _:=0whent=0. ‘ “turd!“ f: «womb é I, V‘" - 1 ‘ “+0.019I‘z-V; y=Jﬂl+OJnl° mat-2000!“- y . 322qu A" It : Id! I III-+0511“ °' ‘ - l2" _Rl=mﬂm+lm+m|. ’- Sou-ml 't=1§\$l A“ ...
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