CH 12 GAS LAWS PRACTICE QUESTIONS ANSWERS

CH 12 GAS LAWS PRACTICE QUESTIONS ANSWERS - a. rnol...

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PC", - a. rnol fraction C& = xCH1 = - - 0.175 atrn = 0.412 I P,,,, + 0.250 atm - P, x V 0.425 atm x 10.5 L b. PV=nRT, n~= - - = 0.161 mol RT 0.08206 L atm 338 rnol K :. xCH, = % , n,, - xCH, x nlMal = 0.412 x 0.161 mol = 6.63 x 10-~mol CI-b nm1 16.04 g CH, 6.63 x 10-~mol CH., x = 1.06gCa rnol CH, no2 = 0.588 x 0.161 rnol = 9.47 x 10-~rnol 02; 9.47 x 10-~rnol O2 x 32.00 g 0, mol0,
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112 &aha._. . - law of effusion: 1 aqd Freon-1 1 = gas 2: 137.4 Ti---- .Ill= - 137'4, MI = 121 g/mol The molar mass of CFzCll is equal to 121 glmol, so Freon-12 is CF2C12.
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CH 12 GAS LAWS PRACTICE QUESTIONS ANSWERS - a. rnol...

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