PAST EXAMS - EXAM 3 - SPRING 07 - WORKED SOLUTIONS

# PAST EXAMS - EXAM 3 - SPRING 07 - WORKED SOLUTIONS - Exam 3...

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Exam 3 Solutions - Spring. 2007 - CHM2045 - Form Code A 1. Use the Clausius-Clapeyron Equation to first calculate the AH0,,: Then find the temperature at which the vapor pressure equals 760rnmHg (i.e., the "normal boiling point") by using this AHoVap and one of the sets of P-T data used before: 0.000207 - 0.003 10 = -.00289 = 1/T2 T2 = 346 K (Answer 4) There are two single bonds between the two H atoms and the central C atom, and there is one double bond between the central C and 0 atom, and since each single bond contains one sigma bond, and each double bond contains one sigma and one pi bond, then there are a total of three sigma bonds and one pi bond in a molecule of formaldehyde (Answer 3) C12C0 is trigonal planar with the central C atom being sp2 hybridized. CHzBrz is tetrahedral with the central carbon atom being sp3 hybridized. C02 and OCN- have a linear shape with the central carbon atoms of each being sp hybridized. (Answer 5)

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C2& has two carbons, each of which are sp2 hybridized, and the product C02 is linear with the carbon being sp hybridized. (Answer 5) There three resonance structures that are all equivalent (same formal charge on S), the S is sp2 hybridized in each structure, and there is no net dipole moment in the molecule (it is nonpolar). (Answer 5) PC13 is a trigonal pyramidal (AX\$!) molecule with a net &pole moment (polar). Therefore the P atom is sp3 hybridized. Each P-Cl bond is polar. (Answer 2) 7.
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## This note was uploaded on 05/31/2008 for the course CHM 2045 taught by Professor Mitchell during the Spring '07 term at University of Florida.

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PAST EXAMS - EXAM 3 - SPRING 07 - WORKED SOLUTIONS - Exam 3...

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