ExtraProblemAnswer - at the high energy end (left); then 2s...

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Below is shown the photoelectron spectrum of an element; the peak intensities are roughly proportional to the numbers of electrons found in the orbitals whose energies are shown. Without looking to identify the molecule based on ionization energies, which element is shown? The element has what would appear to be 1s orbitals
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Unformatted text preview: at the high energy end (left); then 2s and 2p, and at the right end what must be a 3s. All orbitals except that at 5.31 MJ/mol look equally occupied; that would suggest that the 3s is doubly occupied, and the atom is Mg....
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