RECITATION-CH 29-2

RECITATION-CH 29-2 - RECITATION 10 32. The magnetic force...

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Unformatted text preview: RECITATION 10 32. The magnetic force on the wire is ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 mag 3 3 i j k j k 0.50A 0.50m 0.010T j 0.0030T k 2.5 10 N j 0.75 10 N k. y z z y F i L B i L B B i L B B-- = = + =- + =- + = - + r r r 37. The magnetic field can be expressed as ( 29 ( 29 3 1 2 2 cos30 i sin 30 k i k. B B B B B = + = + r The long side opposite the hinge has a length of 10 cm y L = - , and the current through that side flows in the negative y direction, so the force acting on all 20 N = turns of that side is ( 29 ( 29 { } ( 29 3 3 1 1 mag 2 2 2 2 j i j k k i . y y F N i L B N i L B N i L B = =- - =- r r r With the length of the short sides of the loop, this force will produce a torque about the hinge given by ( 29 3 3 1 mag 2 2 2 i k i j. x x y x y L F L N i L B N i L L B = = - = - r r r Each of the other three sides of the coil experiences a force due to the magnetic field, but none...
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RECITATION-CH 29-2 - RECITATION 10 32. The magnetic force...

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