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Unformatted text preview: RECITATION 8 5. (a) The capacitance of a parallelplate capacitor is given by , C A d ε = where A is the area of each plate and d is the plate separation. Since the plates are circular, the plate area is A = π R 2 , where R is the radius of a plate. Thus, ( 29 ( 29 2 2 2 3 8.85pF m 8.2 10 m 140pF. 1.3 10 m R C d π ε π × = = = × (b) The charge on the positive plate is given by , q C V = ∆ , where V ∆ is the potential difference across the plates. Thus, ( 29 ( 29 10 8 1.4 10 F 120 V 1.7 10 C. q = × = × 13. Capacitors 1 C and 2 C are in parallel, so their equivalent capacitance is 12 1 2 15.0?F. C C C = + = That parallel combination is in series with 3 C . The equivalent capacitance of the set of three capacitors is 1 1 123 12 3 1 1 1 1 3.16 F. 15.0 F 4.00 F C C C μ μ μ = + = + = 15. Let x be the separation of the plates in the lower capacitor. Then the plate separation in the upper capacitor is a – b – x . The capacitance of the lower capacitor is ....
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 Spring '08
 Goksu
 Physics, Capacitance, Energy, Inductor

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