RECITATION-CH31

# RECITATION-CH31 - RECITATION 12 5(a Table 26-2 gives the...

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RECITATION 12 5. (a) Table 26-2 gives the resistivity of copper. Thus, ( 29 ( 29 ( 29 8 3 2 3 0.10m 1.69 10 m 1.1 10 . 1.25 10 m L R A π ρ - - - = = × Ω ⋅ = × × (b) The current induced in the loop has a magnitude of mag 2 1 , d r dB i R R dt R dt Φ = = = E where r is the radius of the loop. Therefore, to produce a current of 10 A requires that the field change at a rate of ( 29 ( 29 ( 29 3 2 2 10A 1.1 10 1.4T s. 0.05m i R dB dt r - × = = = 9. Since a square's area is related to the length of its sides by 2 , A = l we have 2 . dA dt d dt = l l Thus, Faraday's law gives the magnitude of the emf as ( 29 ( 29 ( 29 mag 2 2 0.24T 0.12m 0.050m/s 0.0029V. d dA d B B dt dt dt Φ = = = = = l l E 17. (a) Each side of the square has a length of 2.00 m. L = The magnetic flux through the circuit is mag 2 2, BL Φ = and the induced emf has a magnitude of ( 29 ( 29 mag 2 2 2.00 m 0.870T s 1.74V . 2

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## This note was uploaded on 06/01/2008 for the course PHYS 232 taught by Professor Goksu during the Spring '08 term at Millersville.

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RECITATION-CH31 - RECITATION 12 5(a Table 26-2 gives the...

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