HOMEWORK-CH34

# HOMEWORK-CH34 - 29 29 29 2 2 2 2 2 2 1 W m cos 70 cos 20...

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HOMEWORK ASSIGNMENT 7 10. The intensity is ( 29 ( 29 ( 29 ( 29 2 2 max 8 4 6 2 2 7 0 3.0 10 m s 1.0 10 T 1.2 10 W m . 2 2 4 10 H m c B I μ π - - = = = 41. The initial beam has intensity 2 0 43W m I = and is vertically polarized. Since the first polarizing sheet has its polarization axis 70° from the vertical, the intensity of the transmitted light is 2 1 0 cos 70 . I I = The second sheet has a horizontal polarization axis, which is 20° away from the polarization direction of the light that strikes it. Hence, the final intensity of the light, after passage through both polarizing sheets is
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Unformatted text preview: ( 29 ( 29 ( 29 2 2 2 2 2 2 1 cos 20 43W m cos 70 cos 20 4.4W m . I I = = = 46. (a) Since intensity is proportional to the square of the electric field amplitude, the fraction of light intensity transmitted by the glasses is ( 29 2 2 trans 2 2 2 2 0.16. 2.3 v v v h v v E E I I E E E E = = = + + (b) Since now the horizontal component of E will pass through the glasses, ( 29 ( 29 2 2 trans 2 2 2 2 2.3 0.84. 2.3 v h v h v v E E I I E E E E = = = + +...
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## This note was uploaded on 06/01/2008 for the course PHYS 232 taught by Professor Goksu during the Spring '08 term at Millersville.

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