RECITATION-CH34

# RECITATION-CH34 - therefore 2 2 1 1 2 1 1 2 2 8 cos cos 60...

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RECITATION 13 5. If P is the power and t is the time interval of one pulse, then the energy U in a pulse is ( 29 ( 29 12 9 5 100 10 W 1.0 10 s 1.0 10 J. U P t - = ∆ = = 11. (a) The maximum value of the magnetic field is max max 9 8 2.0V m 6.7 10 T. 3.0 10 m s E B c - = = = (b) The intensity is ( 29 ( 29 ( 29 2 max 3 2 7 8 0 2.0V m 5.3 10 W m . 2 2 4 10 H m 3.0 10 m s E I c μ π - - = = = (c) The power of the source is ( 29 ( 29 ( 29 2 2 3 2 4 4 10m 5.3 10 W m 6.7 W. s P r I r - = = = 19. The distance between you and the space heater would be ( 29 2 1000W 0.89 m. 4 4 100W m s P r I = = = 39. Let 0 I be the intensity of the unpolarized light that is incident on the first polarizing sheet. The transmitted intensity through this first sheet is I I 1 1 2 0 = , and the light is polarized at an angle of 1 40 θ = counterclockwise from the y axis. This light makes a 1 2 60 = angle with the polarization axis of the second sheet. The transmitted intensity through the second sheet is

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Unformatted text preview: therefore 2 2 1 1 2 1 1 2 2 8 cos cos 60 . I I I I = = = The light is now polarized at an angle 2 20 = clockwise from the y axis. This light makes an angle of 2 3 60 = with the polarization axis of the third sheet. The transmitted intensity after all three sheets is therefore 2 2 1 1 3 2 2 3 8 32 cos cos 60 . I I I I = = = Thus, 3.1% of the lights initial intensity is transmitted through to the end. 49. The light transmitted through both sheets has an intensity of 2 1 2 2 cos , I I = where I is the intensity of the incident beam and is the angle between the polarization axes of the sheets. For 1 2 3 , I I = they must be at an angle of ( 29 1 2 3 cos 35 .-= =...
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## This note was uploaded on 06/01/2008 for the course PHYS 232 taught by Professor Goksu during the Spring '08 term at Millersville.

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RECITATION-CH34 - therefore 2 2 1 1 2 1 1 2 2 8 cos cos 60...

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