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RECITATION-CH 22

# RECITATION-CH 22 - RECITATION CHAPTER 22 1 The mass of an...

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RECITATION – CHAPTER 22 1. The mass of an electron is m = 9.11 × 10 –31 kg, so the number of electrons in a collection with total mass M = 75.0 kg is 31 31 75.0 kg 8.23 10 electrons. 9.11 10 kg M n m - = = = × × The total charge of the collection is ( 29 ( 29 31 19 13 8.23 10 1.60 10 C 1.32 10 C. q ne - = - = - × × = - × 2. There are two protons (each with charge e ) in each molecule, so there are 2 A N protons in a mole of hydrogen. The total quantity of positive charge is ( 29 ( 29 ( 29 23 19 5 2 2 6.02 10 1.60 10 C 1.93 10 C 0.193 MC. A q N e - = = × × = × = 3. Each electron has charge – e . Removing one electron leaves the coin with charge e . The number of electrons that must be removed to leave a net charge of 7 1.0 10 C q - = × is 7 11 19 1.0 10 C 6.3 10 . 1.6 10 C q n e - - × = = = × × 4. 250 cm 3 of water has a mass of 250 g since the density of water is 1.0 g/cm 3 . Since one mole of water has a mass of 18 g, there are 250/18 = 14 moles of water in this volume. There are ten protons (each with charge e ) in each molecule of H 2 O, so the total quantity of positive charge is ( 29 ( 29 ( 29 ( 29 ( 29 23 19 7 14 10 140 6.02 10 1.60 10 C 1.3 10 C 13MC.

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RECITATION-CH 22 - RECITATION CHAPTER 22 1 The mass of an...

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