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Unformatted text preview: HOMEWORK ASSIGNMENT 4 8. (a) We use Eq. 2817: ( 29 ( 29 ( 29 ( 29 3 3 3 3 4 8.85 pF m 40.0 10 m 38.0 10 m 4 85pF. 40.0 10 m 38.0 10 m ab C b a π πε × × = = = × × (b) Let the area required be A . Then ( 29 , C A b a ε = or ( 29 ( 29 ( 29 ( 29 3 2 2 85 pF 2.0 10 m 0.019 m 190 cm . 8.85 pF m C b a A ε × = = = = 18. (a) First, the equivalent capacitance of the two 4.0 μ F capacitors connected in series is ( 29 4.0 F 2 2.0 F. a C μ μ = = This combination is then connected in parallel with two other 2.0 μ F capacitors (one on each side), resulting in an equivalent capacitance of 2.0 F 2.0 F 6.0 F. b a C C μ μ μ = + + = This combination is in series with another combination (the two 3.0 μ F capacitors in parallel, with an equivalent capacitance of ( 29 2 3.0 F 6.0 F d C μ μ = = ). Thus, the equivalent capacitance of the whole circuit is ( 29 1 eq 6.0 F 1 1 3.0 F. 2 b d C C C μ μ = + = = (b) Let ∆ V = 20 V be the potential difference supplied by the battery. Then = 20 V be the potential difference supplied by the battery....
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This note was uploaded on 06/01/2008 for the course PHYS 232 taught by Professor Goksu during the Spring '08 term at Millersville.
 Spring '08
 Goksu
 Physics, Work

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