ch17 - CHAPTER 17 1. We start with Eq. (17-19) . We define...

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Unformatted text preview: CHAPTER 17 1. We start with Eq. (17-19) . We define k as the z axis. This means that the polarization vector, which is perpendicular to k has the general form ( ) = i cos + j sin This leads to B = A = - i h 2 V k k ( i cos + j sin ) = B ( j cos - i sin ) We are now interested in M = B g p- g n 2 h 2 X {( y ( p )- y ( n ) ) cos - ( x ( p )- x ( n ) ) sin } X 1 m The operators are of the form y cos - x sin =- icos icos - sin sin =- ie- i ie i It is simple to work out the bra part of the scalar product 1 2 + ( p ) - ( n )- - ( p ) + ( n ) ( 29- ie- i ie i p-- ie- i ie i n with the help of +- ie- i ie i = 1 0 ( 29- ie- i ie i =- ie- i ( 29 = - ie- i - and -- ie- i ie i = 0 1 ( 29- ie- i ie i = ie i ( 29 = ie i + This implies that the bra part is 1 2 + ( p ) - ( n )- - ( p ) + ( n ) ( 29- ie- i ie i p-- ie- i ie i n = = - 2 i ( e- i - ( p ) - ( n ) + e i + ( p ) + ( n ) ) = - 2 i e- i X 1- 1 + e i X 1 1 ( 29 For the ket state we may choose X triplet...
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ch17 - CHAPTER 17 1. We start with Eq. (17-19) . We define...

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