MOOREHW11 - Chapter 19: ElECTI‘flChElfliS’EI‘}? and...

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Unformatted text preview: Chapter 19: ElECTI‘flChElfliS’EI‘}? and Its Applications 32. Answer: (a) 2.91 V (b) +0.028 V" (c) 0.65 V (d) 1.16 V; (a), (c) and ((1) are product—favored. Sfmtegv and Erplmmrfon: Use the method described in Problem-Solving Example 19.7. (a) Mg(s) —r Mg2+(aq) + 2 e‘ oxidation half-reaction EORDOde : — 2.37 V" 12(s) + 2 e‘ —n- 2 I‘(aq) reduction half-reaction Limmhmie = +0535 V 12(s) — Mg(s) —» Mg2+(aq) + 21‘(aq) ECCEH : (+0535 V) — (—2.37 V") 2 2.91 V This reaction is product-favored. (b) Ag(5) —-r Ag+(aq) — e‘ oxidation half-reaction Ecauode : — 0.7994 V" Fe3+(aq) + e’ —> Fe2+(aq) reduction half-reaction Eflmflmde = +0.771 V Ag(s) + Fe3_(aq) —r~ Fe2‘(aq) + Ag+(aq) EDGE“ = (— 0.771 V") + (—0.7994 V) = +0028 V This reaction is not product-favored. (c) S112+(aq) —u— 8114+(aq) + 2 e‘ oxidation half-reaction Ecamde =+0.15V 2 Ag+(aq) + 2 e‘ —I- 2 Ag(s) reduction half-reaction E" = +0.7994 V “cathode S112+(aq) + 2 AgTaq) —l- 8114+(aq) + 2 Ag(s E36611 = (+0.7994 V") — (+ 0.15 V") = 0.65 V This reaction is product-favored. (d) 2 211(5) —r 2 le2_(aq) + 4 e‘ oxidation half-reaction E” I — 0.763 V anode 02(3) + 2 H200”) + 4 e‘ —~ 4 OH ‘(aq) reduction half-reaction ED 2 +0.40 V cathode 2 211(5) + 02(5) — 2 H200”) —. 2112+(aq) + 4 OH -(aq) ECCEH : (+0.40 V) — (—0.763 V) 2 1.16 V This reaction is product-favored. 38. Answer: (a) 1.55 V (b) —1196 11.1, 1.55 v Strategv and Erpt'mmtfon.‘ (a) Adapt the method described in Problem-Solving Example 19.8: AGO = 4113153 cell Two 0 atoms are going from OX. 15' = 0 to OX. # = —". So. 11 = 4 11101. _(_598 km 1000 J]x 1C.xl V] E3 _—AG“_ 1kJ_ 11 fig“; Ce“ 11E (4 11101)(96485 C mol) " “ (b) When the reaction is written with all the coefficients doubled: AGOdouble Z 2 X AGO 2 x {—598 kJ) = —1196 kJ original _ 42. Answer: K0 = 1 x 10-13, AGO = 102 kJ .S‘tmtegy mid Erpimmtion: Adapt the method described in the solution to Question 38 and Problem-Solving Example 19.9. 2 Br‘(aq) —> BI2(1’) + 2 e‘ Famed: 13(s) + 2 e‘ —I- 21—(aq) EC cathode : +1066 V : +0535 v 12(s) + 2 Br—(aq) a» 2 I‘(aq)+Br2(f.) Eccen:(+0.535VJ—(+1.066V) 2—0531 v IlEgcll _ (2 11101) >< (—0.531 V) log K0 — 0.0592 V 0.0592 V =—17.9 K0 = 1 x 10-18 1J 11d —>< =102kJ 1C><1V 1000 AG0 2 — (2 11101) >< (96485 011101) x {—0.531 V) >< ...
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This note was uploaded on 06/03/2008 for the course CHEM 1A taught by Professor Nitsche during the Fall '08 term at University of California, Berkeley.

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MOOREHW11 - Chapter 19: ElECTI‘flChElfliS’EI‘}? and...

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