20B_test_1_key

20B_test_1_key - First; MidTerm Examination, CH20B-1,...

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Unformatted text preview: First; MidTerm Examination, CH20B-1, Winter 2008 Friday, 1 February, 10:00 — 10:50 am NAME: This exenniuarion is composed of three problems. Do all parts of all the problems. You have the entire class period to complete the exam. You may use your textbook, one page ul' iotes (from and back) and a calculator of your choice in wcn'king the exam. Problem l: of 35 points Problem 2: of 30 points Problem 3: of 35 points 'l'()'l‘;\li: l (35 points) 0.148 g of a gaseous hydrocarbon having the chemical formula C,,H2,,+2 react s (‘ompletely with an excess of of 02(9) to yield C02(g) and H2()(g). The reaction takes place in a 0.400-L container. Before reaction the pressure and temperature in the (-ontainer are l.8323 atm and 0°C, respectively. After reaction the pressure and temperature are 2.7957 atm and 1000C. respectively. Find the chemical formula of the hydrocarbon (i.e.. determine 71,). You may assume that all gases behave ideally. alw Benzene (CUHU) has its triple point at 562°C and 35.95 Torr and its critical point at 29$).0l”(‘ and 48.34 atm. The density of C(5H6(l) is 0.8787 g/cn'i3 and that of CGH6(S’) is 0.899 g/"enig. (20 points) Sketch a pressure-temperature phase diagram for benzene. There is no need 1o draw the diagram exactly to scale 77 just do the best you can. But do label relevant points on each axis. Also on the diagram label the triple point. (ii) the eritieal point (iii) the normal boiling point“ and (iv) the normal melting point. Also label the single—phase regions with their relevant phases. ( 10 points) Describe the state of a benzene sample during the course of a constant— temperatnre process at 564°C that starts at 100 atm and ends at 0.01 atm. .‘i‘ {‘35 points) The ‘cLIIllIlO acid lysine is known to contain 49.29% C. 9.65% H. 19.16% and 21.89% 0 by mass. A solution of 40 mg of lysine in 1.200 g of hiphcnyl (an orgzuiiv solvent) decreases the freezing point from that of pure biphenyl by 1.830C. DOI’OI‘nliIM‘ tho molecular formula of lysine. [Kf. the freezing point depression constant for Inphonvl is 8.00 K—kg/nroll 02013-/ W’s/Y 5+ MMHm/n ,2/1//08 (D 1 gmw (QM 1 +5 M+l (Ma ('1) + Egg/3) ——; Mom) + % 410/7) ( PW ofa‘” YW W l'): 45’ U , ’ MM- m/thmvgg-fl; ’ _/ , ‘1 2 “$323 min 3.9L 5 3.1é‘78xw mo// ((7.0?20é (2.43. l§ k) x 53 § H §K + '\ Q: Q, 44 09 r-\ k: 3 1s \‘1 <51!qu X/wmm +2,02§¢> + ( r m, {WWW 0.713744 + AW! =m my ': /. Z /'0,?Z37 a/ #40 ’ -5’ C/dX/O W; > a, doli/fi g’o/vcrt‘)‘ \ (/X'Jz W 0.00”.ng . M : 7727/51” / /¢ 1/}? [1/ // - 3.0 MW +3 2' /2m,+ Maw/M + Macy] «L KWV/i =m(/2+/£3§W+/V.ooé7(%) +1512?ng % .2 3 3 + '3 M =2¢/.3‘/7M W7 (a) (l) 1% (Q Miofitffiu M: W +3 Mcfi7gzé ...
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20B_test_1_key - First; MidTerm Examination, CH20B-1,...

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